-26 over 5
-26/5
hope this helps!
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Answer:
The answer is 408
Explanation:
20% of 510 is 102 and 510 - 102 is 408
7 unit to the left, means it is 7 less than -1.
-1-7 = -8
Ans: -8
Answer:
![\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B3sinx-3x%7D%7B7x%5E3%7D%3D-%5Cfrac%7B1%7D%7B14%7D)
Step-by-step explanation:
The limit is:
![\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B3sinx-3x%7D%7B7x%5E3%7D%3D%5Cfrac%7B0%7D%7B0%7D)
so, you have an indeterminate result. By using the l'Hôpital's rule you have:
![\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7Ba%28x%29%7D%7Bb%28x%29%7D%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7Ba%27%28x%29%7D%7Bb%27%28x%29%7D)
by replacing, and applying repeatedly you obtain:
![\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B3sinx-3x%7D%7B7x%5E3%7D%3D%20%5Clim_%7Bx%20%5Cto%200%7D%5Cfrac%7B3cosx-3%7D%7B21x%5E2%7D%3D%20%5Clim_%7Bx%20%5Cto%200%7D%5Cfrac%7B-3sinx%7D%7B42x%7D%3D%20%5Clim_%7Bx%20%5Cto%200%7D%5Cfrac%7B-3cosx%7D%7B42%7D%5C%5C%5C%5C%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B3sinx-3x%7D%7B7x%5E3%7D%3D%5Cfrac%7B-3cos0%7D%7B42%7D%3D-%5Cfrac%7B1%7D%7B14%7D)
hence, the limit of the function is -1/14
Answer:
He lost 147.35 marks
Step-by-step explanation:
Take the total marks and subtract the marks he got to find the marks he lost
600-452.65= 147.35