Question

Pleeasse solve it ill give brainliest please​

Answer 1

Answer:

a) 210 Ω

b) 21 V

c) 0.07 A, 0.03 V

d) VAE = 7 V

VEB = 14 V

VAF = 9 V

VFB = 12 V

Explanation:

a) 100 Ω and 200 Ω are in series, equivalent = 100 + 200 = 300 Ω,

300 Ω and 400 Ω are in series, equivalent = 300 + 400 = 700 Ω

300 Ω and 700Ω are in parallel, so the equivalent resistance between A and B is R where

1/300 + 1/700 = 1/R, get R = 210 Ω

b) Given I = 0.1 A

so VAB = I * R = 1 * 210 = 21.0 V

c) I₁ + I₂ = I = 0.1, so I₂ = 0.1 - I₁

I₁ * 300 = I₂ * 700

I₁ * 300 = (0.1 - I₁) * 700

get I₁ = 0.07 A, I₂ = 0.1 - I₁ = 0.03 A

d) VAE = I₁ * 100 = 7 V

VEB = I₁ * 200 = 14 V

VAF = I₂ * 300 = 9 V

VFB = I₂ * 400 = 12 V