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zloy xaker [14]
4 years ago
13

Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is

Sasha’s tangential speed?
-0.9 m/s
-1.3 m/s
-2.7 m/s
Physics
1 answer:
Leokris [45]4 years ago
6 0

Answer: 2.7 m/s

Explanation:

Given the following :

Period (T) = 8.2 seconds

Radius = 3.5 m

The tangential speed is given as:

V = Radius × ω

ω = angular speed = (2 × pi) / T

ω = (2 × 22/7) / 8.2

ω = 6.2857142 / 8.2

ω = 0.7665505

Therefore, tangential speed (V) equals;

r × ω

3.5 × 0.7665505 = 2.6829268 m/s

2.7 m/s

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A worker drives a 0.562 kg spike into a rail tie with a 2.26 kg sledgehammer. The hammer hits the spike with a speed of 64.4 m/s
zubka84 [21]

Answer:

Explanation:

Given that,

Mass of sledge hammer;

Mh =2.26 kg

Hammer speed;

Vh = 64.4 m/s

The expression fot the kinetic energy of the hammer is,

K.E(hammer) = ½Mh•Vh²

K.E(hammer) = ½ × 2.26 × 64.4²

K.E ( hammer) = 4686.52 J

If one forth of the kinetic energy is converted into internal energy, then

ΔU = ¼ × K.E(hammer)

∆U = ¼ × 4686.52

∆U = 1171.63 J

Thus, the increase in total internal energy will be 1171.63 J.

4 0
4 years ago
What’s the opposite of an electron
Anna007 [38]
As its charge, proton -a positive charged molecule at the center of an atom- is the opposite of the electron -the particle which is orbiting the center of an atom.
7 0
4 years ago
Examples of fixed pulley?​
Neko [114]

Answer:

One example of a fixed pulley is a Flag Pole

Explanation:

A good example of a fixed pulley is a flag pole: When you pull down on the rope, the direction of force is redirected by the pulley, and you raise the flag. Other examples of movable pulleys include construction cranes, modern elevators, and some types of weight lifting machines at the gym.

4 0
3 years ago
In an engine, an almost ideal gas is compressed adiabatically to half its volume. In doing so, 2820 J of work is done on the gas
Dmitry_Shevchenko [17]

Answer:

  1. Q=0
  2. U=2820
  3. Energy increases

Explanation:

From the question we are told that

Work done W=2820

a)Generally the heat flow for an adiabatic process is 0 (zero)

Q= U + W =>0

Q=0

b)Generally Change in internal energy of gas is mathematically given by

Since W=-2820J

Therefore

U=2820

Giving

Q= 2820 -2820

Q=O

c)With increases in internal energy brings increase in temperature

Therefore

Energy increases

3 0
3 years ago
HELP ME PLEASE !!!!!!!!!!!!!!!!!
Shalnov [3]

Answer:

Option D. 6.1 m/s²

Explanation:

We'll begin by calculating the acceleration due to gravity in each case. This is illustrated below:

1. For Rock:

Mass (m) = 20 g

Force (F) = 0.1224 N

Acceleration due to gravity (g) =?

Next, we shall convert 20 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

20 g = 20/1000

20 g = 0.02 kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.02 kg

Force (F) = 0.1224 N

Acceleration due to gravity (g) =?

F = mg

0.1224 = 0.02 × g

Divide both side by 0.02

g = 0.1224/0.02

g = 6.12 m/s²

2. For Grain of sand:

Mass (m) = 0.8 g

Force (F) = 0.00501 N

Acceleration due to gravity (g) =?

Next, we shall convert 0.8 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

0.8 g = 0.8/1000

0.8 g = 0.0008 kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.0008 kg

Force (F) = 0.00501 N

Acceleration due to gravity (g) =?

F = mg

0.00501 = 0.0008 × g

Divide both side by 0.0008

g = 0.00501/0.0008

g = 6.26 m/s²

3. For Metal bolt:

Mass (m) = 79 g

Force (F) = 0.4871 N

Acceleration due to gravity (g) =?

Next, we shall convert 79 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

79 g = 79/1000

79 g = 0.079kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.079 kg

Force (F) = 0.4871 N

Acceleration due to gravity (g) =?

F = mg

0.4871 = 0.079 × g

Divide both side by 0.079

g = 0.4871/0.079

g = 6.17 m/s²

From the above calculation we obtained the following values for acceleration due to gravity (g):

Object >>>> Acceleration due to gravity

Rock >>>>> 6.12 m/s²

Sand >>>>> 6.26 m/s²

Metal >>>>> 6.17 m/s²

Thus, closest approximation of the acceleration due to gravity of the planet is 6.1 m/s²

6 0
3 years ago
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