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kiruha [24]
1 year ago
15

12,3,14,10,13,8 step 3 of 3 : determine if the data set is unimodal, bimodal, multimodal, or has no mode. identify the mode(s),

if any exist.
Physics
1 answer:
strojnjashka [21]1 year ago
3 0

The data set has no mode

<h3>What is a mode?</h3>

This is the term used to describe a number in a given data that has the highest frequency.

If a pericular number have more than one frequency in a given data, the number is called the mode. Hence it is describe as unimodal.

If two different number have the same frequency that is more than one, it called bimodal.

If three or more different number have the same frequency that is more than one, it called multimodal

With the above information, we can determine whether or not the data has mode and the kind of mode. Details below

<h3>How to determine the mode</h3>
  • Data in increasing order: 3, 8, 10, 12, 13, 14
  • Mode =?

From the data given, we can see that no number has more than one frequency.

Thus, the data has no mode

Learn more about mode:

brainly.com/question/300591

#SPJ1

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8 0
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Some trees have red leaves all year long. You know that plants with green leaves make their food for themselves. How do you thin
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Read 2 more answers
two horses are pulling a 325 kg wagon, initially at rest. The horses exert 250 N and 178 N forward forces, respectively. Ignorin
Dovator [93]

Answer:

AFter 3.5 s, the wagon is moving at:   4.62\,\,\frac{m}{s}

Explanation:

Let's start by finding first the net force on the wagon, and from there the wagon's acceleration (using Newton's 2nd Law):

Net force = 250 N + 178 N = 428 N

Therefore, the acceleration from Newton's 2nd Law is:

F=m\,*\,a\\a = \frac{F}{m} \\a= \frac{428}{325}\, \frac{m}{s^2} \\a\approx 1.32 \,\,\frac{m}{s^2}

So now we apply this acceleration to the kinematic expression for velocity in an object moving under constant acceleration:

v_f=v_i+a\,*\,t\\v_f=0+1.32\,*\,3.5\,\,\frac{m}{s} \\v_f=4.62\,\,\frac{m}{s}

7 0
3 years ago
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