The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.
<h3>What is absolute pressure?</h3>
Absolute pressure is the force that exists in a space when there is no matter present, or when there is a perfect vacuum. This absolute zero serves as the baseline for measurements in absolute pressure. The measurement of barometric pressure is the greatest illustration of an absolute referenced pressure. In order to determine absolute pressure, a complete vacuum is used. In contrast, gauge pressure is the amount of pressure that is measured in relation to atmospheric pressure, also referred to as barometric pressure.
given,
diameter = 6 m
depth = h = 1.5 m
Atmospheric pressure = P₀ = 10⁵ Pa
a) absolute pressure
P = P₀ + ρ g h
P = 10⁵ + 1000 x 10 x 1.5
P = 1.15 x 10⁵ Pa
b) When two person enters into the pool,
mass of the two person = 150 Kg
weight of water level displaced exists equal to the weight of person.
Area of pool 
Height of the water rise
P = ρ g h
P = 1000 x 10 x 0.0106
P = 106.103 Pa
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The equation for force is F=ma. Because we have the value of mass (0.42 kg) and the acceleration (14.8 m/s^2), simply plug them into the equation for force to get
The answer is 6.22 N because newtons are the unit used to measure force.
Molecular mass may be calculated by taking the atomic mass of each element present and multiplying it by the number of atoms of that element in the molecular formula. Then, the number of atoms of each element is added together. This value may be reported as a decimal number or as 16.043 Da or 16.043 amu.
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Answer:
V_f = 287.04 mL
Explanation:
We are given the initial/original volume of the glycerine as 285 mL.
Now, after it is finally cooled back to 20.0 °C , its volume is given by the formula;
V_f = V_i (1 + βΔT)
Where;
V_f is the final volume
V_i is the original volume = 285 mL
β is the coefficient of expansion of glycerine and from online tables, it has a value of 5.97 × 10^(-4) °C^(−1)
Δt is change in temperature = final temperature - initial temperature = 32 - 20 = 12 °C
Thus, plugging in relevant values;
V_f = 285(1 + (5.97 × 10^(-4) × 12))
V_f = 287.04 mL
