1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
insens350 [35]
4 years ago
11

Tectonic plates are large segments of the earth's crust that move slowly. suppose one such plate has an average speed of 4.8 cm

per year. (a) what distance does it move in 40 seconds at this speed?
Physics
1 answer:
user100 [1]4 years ago
6 0
<span>one year is 365, 1 day is 24 hours, 1 hour is 60 minutes, 60 minutes is 60 seconds, thus (365 * 24 * 60 * 60) = 31,536,000 one year is equal to 31,536,000 seconds. the plate has a speed of 4.8 cm every 31,536,000 seconds. lets find out how far it goes in 40 seconds. (4.8/31,536,000)*40 = 0.00000608828 The plate moves 0.00000608828 cm every 40 seconds</span>
You might be interested in
1.) A negative charge of -2.0x10-4 C and a positive charge of 8.0x10-4 C are
exis [7]

Answer:

The Force between the two charges is an attractive force of 16,000N

Explanation:

Expression for the electric force between the two charges is given by

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = - 2.0x10^-4C

q2 = + 8.0x10^-4C

r = 0.30 m

Substitute the given values in the above expression -

One charge  is + and the other is a -, therefore the net force is an attractive force (opposites atract)

The attraction force is:

F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2

F= 16,000N

6 0
3 years ago
a kid is on a skate board going 14kph and trows a set of keys on the ground at 8kph. the spped of the keys relitive to the gound
Vanyuwa [196]
To determine the speed relative to the ground, since the ground is our reference frame, it would be v = 0, for the kid on the skateboard, you would need to take into account the speed that he/she is going and the speed of the keys thrown at.

I believe.
5 0
3 years ago
A car of mass 1600 kg traveling at 27.0 m/s is at the foot of a hill that rises vertically 135 m after travelling a distance of
Zarrin [17]

Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.  

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

K_1 = K_2 + P + W

then, the work done by the engine is:

W = K_1 - K_2 - P

The formulas for the Kinetic and potential energy are:  

K=\frac{1}{2}mV^2\\P=mgh

where, m is the mass of the car, V the velocity, g the gravity and h is the elevation of the hill.

Using the formulas:

W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh

Replacing the values:

W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

t=\frac{3200m}{20m/s}=160s

the power delivered by the car's engine was:

power=\frac{work}{time}=\frac{1690400J}{160s}=10565W

8 0
4 years ago
HELP PLZ
Anon25 [30]

Answer:

A = 11.77 m/s²

Explanation:

Mass of box (m) = 66kg

Force (f) = 777n

Acceleration (a) = ??

F = ma

777 = 66 · a

A = \frac{777}{66} = 11.77m/s²

5 0
3 years ago
Read 2 more answers
An earth satellite remains in orbit at a distance of 13594 km from the center of the earth. what is its period? the universal gr
ZanzabumX [31]
Given: Mass of earth Me = 5.98 x 10²⁴ Kg
           Radius of satellite - radius of the earth

           r = 13,594 Km - 6,380 Km = 7,214 Km    convert to meter "m"

           r = 7,214,000 m
            G = 6.67 x 10⁻¹¹ N.m²/Kg²
Required: What is the period T = ?
Formula: F = ma;  F = GMeMsat/r²     Centripetal acceleration ac = V²/r
               but V = 2πr/T
equate T from all equation.
F = ma
GMeMsat/r² = Msat4π²/rT²    
GMe = 4π²r³/T²
T² = 4π²r³/GMe  

T² = 39.48(7,214,000 m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 1.48 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 37,092,731.83 s²

T = 6,090.38 seconds    or  1.7 Hr

6 0
3 years ago
Other questions:
  • Lena is playing with a remote-controlled car in her backyard. She knows that the car uses a wheel and axle to move. What is the
    12·1 answer
  • HELP ASAP!!! So stressed! :(
    6·1 answer
  • The distance light travels in a year is called _______.
    12·2 answers
  • Two internal factors that are important in advancing the cell cycle are
    10·1 answer
  • Once a sound recording is made, how is the sound reproduced? by converting passive sound waves into active sound waves by conver
    8·2 answers
  • A particle that has mass m and charge q enters a uniform magnetic field that has magnitude B and is directed along the x axis. T
    10·1 answer
  • Your car's 30.0 W headlight and 2.50 kW starter are ordinarily connected in parallel in a 12.0 V system. What power (in W) would
    15·1 answer
  • )) What do these two changes have in common?
    8·1 answer
  • In the graph below, why does the graph stop increasing after 30 seconds?
    15·1 answer
  • the aeroplane in fig 3.1 flies an outward journey from Budapest (Hungary) to palermo (Italy) in 2.75 the distance is 2200 KM (i)
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!