1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
galina1969 [7]
2 years ago
12

Que es una variable independiente ?

Physics
1 answer:
nlexa [21]2 years ago
7 0

Answer:

Variable independiente

Explanation:

una variable independiente. Es una variable que está sola y no es modificada por las medidas de otras variables

You might be interested in
the refractive index is the blank of the speed of light in a medium to the speed of light in a vacuum
andrew11 [14]

Answer:ratio

Explanation:

8 0
3 years ago
Read 2 more answers
The atomic mass of gold is 0.197 kg/mole. how many moles are in 0.566 kg of gold.
iogann1982 [59]

Explanation:

0.566kg *(1mol/0.197 kg)= 2.87 mol gold

note how the units cancel out, if the units do not cancel out (kg/kg=1) then u did something wrong

7 0
3 years ago
Read 2 more answers
What is the density (in kg/m3) of a woman who floats in freshwater with 4.92% of her volume above the surface
kipiarov [429]

Answer:

The density of the woman is 950.8 kg/m³

Explanation:

Given;

fraction of the woman's volume above the surface = 4.92%

then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%

the specific gravity of the woman = \frac{95.08}{100 } = 0.9508

The density of the woman is calculate as;

Specific \ gravity \ of \ the \ woman = \frac{Density \ of \ the \ woman }{Density \ of \ fresh \ water }\\\\ Density \ of \ the \ woman  = Specific \ gravity \ of \ the \ woman \ \times \ Density \ of \ fresh \ water

Density of fresh water = 1000 kg/m³

Density of the woman = 0.9508 x 1000 kg/m³

Density of the woman = 950.8 kg/m³

Therefore, the density of the woman is 950.8 kg/m³

4 0
3 years ago
A circular wire loop of radius 15.0 cm carries a current of 2.60
Korolek [52]
Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm
5 0
3 years ago
The zinc plate is coated with mercury ​
raketka [301]
Amalgamating is the coating of zinc plate with mercury.
8 0
3 years ago
Other questions:
  • Most comets come from an area called the oort cloud true or false
    6·2 answers
  • 8 points
    12·2 answers
  • Object A has mass mA = 9 kg and initial momentum vector pA,i = < 20, -6, 0 > kg · m/s, just before it strikes object B, wh
    13·1 answer
  • Calculate the force of gravity acting on an object that has a mass of 1.3 kilograms. The object is on Earth soyuz 9.8 m / S 2 fo
    7·1 answer
  • Given a block of glass that is semi-circular, a laser pointer, protractor/ruler, and index card, design your own experiment to o
    15·2 answers
  • g Warm water in a geothermal heating system enters the pipe of a radiator at 20 psia and 119oF with a flow rate of 235 cfm (ft3/
    14·1 answer
  • How did Mendel explain the results of crossing 2
    14·1 answer
  • A car is going through a dip in the road whose curvature approximates a circle of radius 200 m. At what velocity will the occupa
    14·1 answer
  • [OSS.04H]The diagram below shows a star map.
    5·1 answer
  • Convert:<br> 1) 2kg into gram<br> 2) 5200m into km<br> 3) 20cm into m
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!