The applications, either for diagnostic purposes or for therapeutic purposes, involve the use of X-rays----CT scan radiography ,external beam radiation therapy, fluoroscopy.
How is CT used for treatment planning?
CT planning enables more accurate localisation of both tumour and normal organs in addition to providing an accurate body contour and inhomogeneity corrections.
What is difference between CT scan and fluoroscopy?
Overall, fluoroscopy is a safe procedure, but potential risks include burns or radiation-induced injuries to the skin. On the other hand, CT scans are still snapshots of a “slice” of the body. They use X-rays to help your doctor view important organs
What is a fluoroscopic procedure?
During a fluoroscopy procedure, an X-ray beam is passed through the body. The image is transmitted to a monitor so the movement of a body part or of an instrument or contrast agent (“X-ray dye”) through the body can be seen in detail
Learn more about diagnosis:
brainly.com/question/11681931
#SPJ4
Answer:
Qsinθ/4πε₀R²θ
Explanation:
Let us have a small charge element dq which produces an electric field E. There is also a symmetric field at P due to a symmetric charge dq at P. Their vertical electric field components cancel out leaving the horizontal component dE' = dEcosθ = dqcosθ/4πε₀R² where r is the radius of the arc.
Now, let λ be the charge per unit length on the arc. then, the small charge element dq = λds where ds is the small arc length. Also ds = Rθ.
So dq = λRdθ.
Substituting dq into dE', we have
dE' = dqcosθ/4πε₀R²
= λRdθcosθ/4πε₀R²
= λdθcosθ/4πε₀R
E' = ∫dE' = ∫λRdθcosθ/4πε₀R² = (λ/4πε₀R)∫cosθdθ from -θ to θ
E' = (λ/4πε₀R)[sinθ] from -θ to θ
E' = (λ/4πε₀R)[sinθ]
= (λ/4πε₀R)[sinθ - sin(-θ)]
= (λ/4πε₀R)[sinθ + sinθ]
= 2(λ/4πε₀R)sinθ
= (λ/2πε₀R)sinθ
Now, the total charge Q = ∫dq = ∫λRdθ from -θ to +θ
Q = λR∫dθ = λR[θ - (-θ)] = λR[θ + θ] = 2λRθ
Q = 2λRθ
λ = Q/2Rθ
Substituting λ into E', we have
E' = (Q/2Rθ/2πε₀R)sinθ
E' = (Q/θ4πε₀R²)sinθ
E' = Qsinθ/4πε₀R²θ where θ is in radians
Answer:
When Momentum is conserved it is called conservation of momentum
Explanation:
Answer:
<em>(a) t = 4.52 sec</em>
<em>(b) X = 1,156.49 m</em>
Explanation:
<u>Horizontal Launching
</u>
If an object is launched horizontally, its initial speed is zero in the y-coordinate and the horizontal component of the velocity 
remains the same in time. The distance x is computed as
.
(a)
The vertical component of the velocity 
starts from zero and gradually starts to increase due to the acceleration of gravity as follows
This means the vertical height is computed by
Where 
is the initial height. Our fighter bomber is 100 m high, so we can compute the time the bomb needs to reach the ground by solving the above equation for t knowing h=0
(b)
We now compute the horizontal distance knowing 
