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Kaylis [27]
3 years ago
5

A 100g object begins falling from a height of 5 meters. If g, the acceleration of gravity, is 10 m/s2, how long do you calculate

it will be before the object reaches the ground? (Recall the formula for distance with constant acceleration from zero speed is ½at2.) 0.5 s 1.0 s 5.0 s 10 s 50 s
Physics
1 answer:
zmey [24]3 years ago
7 0

Answer:

The correct option is b: 1.0 s.

Explanation:

To find the time (t) at which the object reaches the ground we need to use the next equation:

y_{f} = y_{0} + v_{0}t - \frac{1}{2}gt^{2}   (1)

Where:

y_{f}: is the final height = 0                    

y_{0}: is the initial height = 5 m

v_{0}: is the initial speed = 0 (it falls from rest)

g: is the gravity = 10 m/s²

By entering the above values into equation (1) we have:

0 = 5m - \frac{1}{2}10 m/s^{2}t^{2}

t = \sqrt{\frac{2*5 m}{10 m/s^{2}}} = 1 s

Therefore, the correct option is b: 1.0 s.

I hope it helps you!    

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Yuri [45]

Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

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3 years ago
magine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and rad
DerKrebs [107]

Without counting wind resistance, They will both reach the ground at the same time. If we apply the concept of kinematics, such as the equation vf^2=vi^2 + 2ad. This equation doesn't count how big or how heavy the mass is, it only focuses on how fast where they in the start and how far are both of them from the ground. So if they both have the same distance and same initial veloctity, then they will reach the ground at the same time.

For example, Try dropping a pen and a paper(Vertically) at the same height, you'll see they'll reach the ground at the same time.

If you count wind resistance, the heavier ball will hit the ground faster, because the air molecules will resist the lighter ball compared to the heavier ball.

6 0
3 years ago
Someone please help
saul85 [17]

Based on the attached image:

  • The name of the longitude line that passes through point A is the International Date Line
  • The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
  • The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
  • Longitude 120° is B
  • Solar time at Point B is 4 pm
  • The location will correspond to any point on the same latitude as A

<h3>What are lines of longitude?</h3>

Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.

Longitude lines divide the earth into semi-circles.

Longitude lines are known as meridians and each meridian measures one arc degree of longitude.

Considering the attached image:

  • The name of the longitude line that passes through point A is the International Date Line
  • The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
  • The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
  • Longitude 120° is B
  • Solar time at Point B is 4 pm
  • the location will correspond to any point on the same latitude as A

In conclusion, longitude lines are imaginary lines and run from North to South on the earth.

Learn more about lines of longitude at: brainly.com/question/1939015

#SPJ1

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Answer:

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MA_775_DIABLO [31]
I got answer c but im not 100% sure 

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