Answer:
1. B. Increase
2. A. Decrease
Explanation:
To understand this issue, we need to put some values and using the ohm's law we can corroborate the two situations.
Ohm's law:
![V = I*R\\where:\\I = current[A] ampers\\R = resistance [ohms]\\V = voltage [volts]\\](https://tex.z-dn.net/?f=V%20%3D%20I%2AR%5C%5Cwhere%3A%5C%5CI%20%3D%20current%5BA%5D%20ampers%5C%5CR%20%3D%20resistance%20%5Bohms%5D%5C%5CV%20%3D%20voltage%20%5Bvolts%5D%5C%5C)
Now for the voltage we will use V = 110 [V], for resistance R = 10 [ohms]
Replacing the values we have:
![I = \frac{V}{R} \\\\I = \frac{110}{10}\\I= 11 [amp]](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BV%7D%7BR%7D%20%5C%5C%5C%5CI%20%3D%20%5Cfrac%7B110%7D%7B10%7D%5C%5CI%3D%2011%20%5Bamp%5D)
Now let's double the voltage 220 [V]:
Therefore the current will be increased.
Let's do the same for the resistance if originally we have R = 10 [ohms]
![I = \frac{V}{R}\\I = \frac{110}{10} \\I = 11 [amp]\\](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BV%7D%7BR%7D%5C%5CI%20%3D%20%5Cfrac%7B110%7D%7B10%7D%20%5C%5CI%20%3D%2011%20%5Bamp%5D%5C%5C)
Now let's double the resistance 20 [ohms]:
![I=\frac{110}{20}\\I = 5.5 [amp]](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B110%7D%7B20%7D%5C%5CI%20%3D%205.5%20%5Bamp%5D)
Therefore the current will be decreased.
Answer:
option A is the correct answer
<span>If your options are:
A.Both momentum and kinetic energy are vector quantities.
B.Momentum is a vector quantity and kinetic energy is a scalar quantity.
C.Kinetic energy is a vector quantity and momentum is a scalar quantity.
D.Both momentum and kinetic energy are scalar quantities.
</span>
The answer on the question given is letter B.<span>Momentum is a vector quantity and kinetic energy is a scalar quantity.</span>
Power is the scientific term defined as the rate at which
work is accomplished. Power can be seen everywhere as it is applied to our
everyday living. Power is seen when one pushes a heavy cart. It could be seen
when a baseball hitter hits the ball.
<span> </span>