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stira [4]
2 years ago
5

3. Use the polynomial 12x^4 y^2 + 30x^3 y to answer the following questions?

Mathematics
1 answer:
barxatty [35]2 years ago
7 0

Answer:

\huge\boxed{GCF:6x^3y}

\huge\boxed{Factored: 6x^3y(2x+5)}

Step-by-step explanation:

Look at both terms separately, and isolate each "part."

i.e. 12x^4y^2 becomes 12, x^4, y^2

So the problem becomes:

12, x^4, y^2 and

30, x^3, y^1

Then, find the GCF of each term,

30 and 12 - 6

x^4 and x^3 - x^3

y^2 and y^1 - y^1

Hope it helps :) and let me know if you want me to elaborate.

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Step-by-step explanation:

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3 years ago
Which of the following expressions is equal to 3x^2 + 27
Kisachek [45]
Factor: 
3x^2 + 27
= 3(x^2  + 9)
Answer is 3(x^2 + 9), when factored.


A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2



B) (3x - 9i)(x + 3i)
= (3x +  - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2


C) (3x - 6i)(x + 21i)
= (3x +  - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
=  - 126i^2 + 57ix + 3x^2






D) (3x - 9i)(x - 3i)
=  (3x +   - 9)(x +  - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x









Hope that helps!!!

8 0
3 years ago
Read 2 more answers
Evelina took 50 people fishing each day last week. The table shows the number of fish the group caught each day.
Alisiya [41]

Answer:

152

Step-by-step explanation:

The amount of fish caught is at a constant decreasing rate of 17. 203-186=17, 186-169=17, 169-17=152. So all you have to do is subtract the constant rate from the last known number.


8 0
3 years ago
Read 2 more answers
Help please!
larisa86 [58]

Answer:

The point at (-7, -5) = a

The point at (9, 3) = b

The point at (-3, 7) = c

The "a" point of the triangle is 12 units away from the center point.

So, 12 x 1/4

=> 12/4

=> 3

So, the "a" point of the dilated figure is  3 units left from the center.

=> So, the dilated "a" point is at (2, -5)

The "b" point is 8/4 (= rise/run = y-axis / x-axis) from the center point.

=> 8/4 = 2

So, the "b" point of the dilated figure is 1 unit right and 2 units up from the center point.

=> So, the dilated "b" point is at (6, -3)

The "c" point is 12/8 units away from the center point.

=> 12/8 x 1/4

=> 3/2

So, the "c" point of the dilated figure is 3 units up and 2 units left from the center point.

=> So, the dilated "c" point is at (3, -2)

7 0
3 years ago
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