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stira [4]
2 years ago
5

3. Use the polynomial 12x^4 y^2 + 30x^3 y to answer the following questions?

Mathematics
1 answer:
barxatty [35]2 years ago
7 0

Answer:

\huge\boxed{GCF:6x^3y}

\huge\boxed{Factored: 6x^3y(2x+5)}

Step-by-step explanation:

Look at both terms separately, and isolate each "part."

i.e. 12x^4y^2 becomes 12, x^4, y^2

So the problem becomes:

12, x^4, y^2 and

30, x^3, y^1

Then, find the GCF of each term,

30 and 12 - 6

x^4 and x^3 - x^3

y^2 and y^1 - y^1

Hope it helps :) and let me know if you want me to elaborate.

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Use braces and digits to designate the set of natural numbers.
alina1380 [7]

Answer:

N = \{1,2,3,4,5,6,.....\}

Step-by-step explanation:

Required

Determine the sets of natural number

Represent this set with letter N

From definition of natural numbers, they are integer numbers starting from 1;

In other words: 1,2,3,4,5, and so on.

To represent this as a set of N, we have

N = \{1,2,3,4,5,6,.....\}

<em>The ..... means that the counting still continues</em>

6 0
4 years ago
Which is longer 4000ft or 1 kilometer
sergejj [24]

Answer:

4000 ft

Step-by-step explanation:

There is 3280.84 foot in km.

So, that makes the 4000 ft the longest.

6 0
3 years ago
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What’s the derivative of sin^2(cos(x^2))
Varvara68 [4.7K]

Answer: f'(x) = - cos^2(sin(x^2))

Step-by-step explanation:

Derivative of:

f(x) = Sin^2(cos(x^2))

f'(x) = cos^2(-sin(x^2)

f'(x) = - cos^2(sin(x^2))

7 0
3 years ago
Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

6 0
3 years ago
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Find the exact length of the third side.<br> 41<br> 9 <br> what’s the other side
vazorg [7]

Step-by-step explanation:

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