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2 years ago

Explain how the property of density is applied and used in the real world

Physics

2 answers:

salantis [7]2 years ago

5 0

Answer:

One well-known application of density is determining whether or not an object will float on water. If the object's density is less than the density of water, it will float; if its density is less than that of water, it will sink. ... In fact, submarines dive below the surface of the water by emptying their ballast tanks.

HOPE IT HELPS

irina [24]2 years ago

3 0

Answer:

Explain how the property of density is applied and used in the real world

<em>One well-known application of density is determining whether or not an object will float on water. If the object's density is less than the density of water, it will float; if its density is less than that of water, it will sink. ... In fact, submarines dive below the surface of the water by emptying their ballast tanks.</em>

Explanation:

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For your answer to this problem, just type in the numerical magnitude of the momentum - no units.

stepan [7]

Answer:

120 kg•m/s.

Explanation:

From the question given above, the following data were obtained:

Case 1

Mass of object = M

Velocity of object = V

Momentum = 15 kg•m/s

Case 2

Mass of object = 2M

Velocity of object = 4V

Momentum = ?

Momentum is defined as follow:

Momentum = mass × velocity

The momentum of object in case 2 can be obtained as follow:

From case 1

Momentum = mass × velocity

15 = M × V

15 = MV ....... (1)

From case 2:

Momentum = mass × velocity

Momentum = 2M × 4V

Momentum = 8MV ....... (2)

Finally , substitute the value of MV in equation 1 into equation 2.

Momentum = 8MV

MV = 15

Momentum = 8 × 15

Momentum = 120 kg•m/s

Therefore, an object with a mass of 2M and 4V would have a momentum of 120 kg•m/s

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3 years ago

If a distance-time graph contains the point (4, 15), what does that tell you about the runner?

serg [7]

Explanation:

It is given that there is distance time graph. The slope of any distance time graph will give the speed or velocity of the object.

In the context, it is seen that there is a point in the distance - time graph. And the values of the point in the graph is (4,15).

Now here, the distance is plotted in the ordinate or the vertical y-axis while time is plotted in the abscissa or the horizontal x-axis.

Thus the point (4,15) tells us that the object has traveled 15 units in time equal to 4 seconds.

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Explanation:

We have to resolve the velocity vector along the east and south axis.

Taking east as positive x-direction and south as positive y-direction, the components of the velocity are given by:

$v_x = v cos \theta\\v_y = v sin \theta$

where

v = 4.3 m/s is the magnitude of the velocity

$\theta=25^{\circ}$ is the angle between the direction of the velocity and of the x-axis

Substituting into the equations, we find:

East component:

$v_x = (4.3)(cos 25^{\circ})=3.9 m/s$

South component:

$v_y = (4.3)(sin 25^{\circ})=1.8 m/s$

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