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3 years ago

Physics Help Please:

2 answers:

8 0

Assume orange is going from left to right and apple is going from right to left
If mv is the momentum of apple at angle θ to the x axis,
In the x direction
0.130*v cos θ = (0.170*1.23) -(0.130*1.08)
0.130*v cos θ = 0.0687-------------------------2

In the y direction
0.130*v sin θ = (0.170*0.974) = 0.16558--------------1

From 1 and 2
tan θ = 2.41

θ = 74.96º
Substituting the value of θ in
0.130*v cos θ = 0.0687

v = 1.38 m/s
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zmey [24]3 years ago

8 0

It would most likely be east or west... use the process of elimination to decide!!!

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A car is initially traveling at 12 m/s when the driver sees a yellow light ahead. He accelerates at a constant 7 m/s^2 for 6 s i

Vitek1552 [10]

Answer:

v = 54m/s

Explanation:

$a = \frac{v - u}{t}$

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u = 12m/s

t = 6s

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(Correct me if i am wrong)

3 0

3 years ago

Three arrows are shot horizontally. They have left the bow and are traveling parallel to the ground. Air resistance is negligibl

timurjin [86]

Answer:

F₁ = F₂ = F₃ = 0 N

Explanation:

given,

Arrow 1 mass = 80 g speed = 10 m/s

Arrow 2 mass = 80 g speed = 9 m/s

Arrow 3 mass = 90 g speed = 9 m/s

Horizontal Force:- F₁ , F₂ and F₃

There is no air resistance.

If Air resistance is zero then the horizontal acceleration of the arrow also equal to zero.

We know,

According to newton's second law

F = m a

If Acceleration is equal to zero

Then Force is also equal to zero.

Hence, F₁ = F₂ = F₃ = 0 N

4 0

3 years ago

If earth had no atmosphere, would a falling object ever reach terminal velocity?

stepan [7]

No, because terminal velocity is when the acceleration of the Earth’s gravity is balanced by the air resistance of the atmosphere.

5 0

3 years ago

How long must a 0.70-mm-diameter aluminum wire be to have a 0.40 a current when connected to the terminals of a 1.5 v flashlight

Natalka [10]

By using Ohm's law, we can find what should be the resistance of the wire, R:
$R= \frac{V}{I}= \frac{1.5 V}{0.40 A} =3.75 \Omega$

Then, let's find the cross-sectional area of the wire. Its radius is half the diameter,
$r=35 mm=0.35 \cdot 10^{-3} m$
So the area is
$A=\pi r^2 = \pi (0.35 \cdot 10^{-3} m)^2=3.85 \cdot 10^{-7} m^2$

And by using the resistivity of the Aluminum, $\rho=2.65 \cdot 10^{-8} \Omega m$ , we can use the relationship between resistance R and resistivity:
$R= \frac{\rho L}{A}$
to find L, the length of the wire:
$L= \frac{RA}{\rho}= \frac{(3.75 \Omega)(3,85 \cdot 10^{-7} m^2)}{2.65 \cdot 10^{-8} \Omega m}=54.48 m$

4 0

3 years ago

A fin whale is swimming at the speed of 35 km/h how many hours will it take to swim 7 km

Aleks04 [339]

Answer:

0.2 hours

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$\frac{7}{35} = 0.2$

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