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loris [4]
3 years ago
12

Physics Help Please:

Physics
2 answers:
Yanka [14]3 years ago
8 0
Assume orange is going from left to right and apple is going from right to left 
If mv is the momentum of apple at angle θ to the x axis, 
In the x direction 
0.130*v cos θ = (0.170*1.23) -(0.130*1.08) 
0.130*v cos θ = 0.0687-------------------------2 

In the y direction 
0.130*v sin θ = (0.170*0.974) = 0.16558--------------1 

From 1 and 2 
tan θ = 2.41 

θ = 74.96º 
Substituting the value of θ in 
0.130*v cos θ = 0.0687 

v = 1.38 m/s 
<span>======================</span>
zmey [24]3 years ago
8 0
It would most likely be east or west... use the process of elimination to decide!!!
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Now imagine a person dragging a 50 kg box along the ground with a rope, as
ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

                                                     = 50 x 9.8

                                                     = 490 N

The coefficient of friction,

                            μ = f/ η

                               = 30 / 490

                               = 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0
3 years ago
In figures (a)-(d), a block moves to the right in the positive x direction through the displacement Δx while under the influence
Elena L [17]

-------ca>a>b>s---c>a>d>b©©s>c>a>b

5 0
2 years ago
What is the force on a 1025 kg elevator that is falling freely at 9.8 m/sec 2?
kicyunya [14]

Answer:

<h2><u>Given </u><u>:</u><u>-</u></h2>
  • Mass = 1025 kg
  • Acceleration = 9.8 m/s²
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>

Force

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

We know that

F = mg

F = 1025 × 9.8

F = 10,045 N

Or,

10045/1000 = 10.045 Kilo Newton

\\

6 0
2 years ago
The ratio between the force of sliding friction and the normal force of an object is called?
Vanyuwa [196]
The answer is the starting friction
5 0
2 years ago
Read 2 more answers
If you want to increase the gravitational force between two objects; would you rather double the mass of one object or halve the
Step2247 [10]

To solve this problem we will apply the concepts related to the Force of gravity from Newtonian theory for which it is necessary to

F = \frac{GMm}{R^2}

Where,

G = Gravitational universal constant

M = Mass of Earth

m = mass of Object

x = Distance between center of mass of the objects.

From this equation we can observe that the Force is inversely proportional to the squared distance between the two objects. The greater the distance, the lower the force of gravity and vice versa.

F \propto \frac{1}{R^2}

If you want to increase the force of gravity, you need to reduce the distance of the two. Therefore the correct option is B. Talk to the distance between them.

5 0
3 years ago
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