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Leno4ka [110]
3 years ago
8

A glass tube 1 mm in diameter is dipped into glycerin. The density of the glycerin is 1260 kg/m3, surface tension is 6.3x10-2 N/

m, and the contact angle is zero. The capillary rise of the glycerin is most nearly:
Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

The capillary rise of the glycerin is most nearly  y  =  0.0204 \ m

Explanation:

From the question we are told that

  The diameter of the glass tube is  d =  1 \ mm =  0.001 \ m

   The density of glycerin is  \rho =  1260 \ kg /m^3

   The surface tension of the glycerin is \sigma   =  6.3 *10^{-2} \ N /m

The capillary rise of the glycerin is mathematically represented as

       y  =  \frac{4 * \sigma  *  cos (\theta )}{ \rho * g *  d}

substituting value  

       y  =  \frac{4 * 6.3 *10^{-2}  *  cos (0 )}{ 1260 * 9.8 *  0.001}

      y  =  0.0204 \ m

Therefore the height  of the glass tube  the glycerin was able to cover is

y  =  0.0204 \ m  

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A hot-air balloon consists of a basket hanging beneath a large envelope filled with hot air. A typical hot-air balloon has a tot
Deffense [45]

Answer:

1.05045 kg/m³

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The net force on the balloon will be

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Also

F_n=m_ag

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4 0
3 years ago
WILL MARK BRAINLIEST PLEASE HELP AND SHOW ALL WORK
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a. 13.23 N

b. 13.2

What you need to do is use this equation:

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<u><em>hope it helps!</em></u>

3 0
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yaroslaw [1]

Answer:

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5 0
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