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77julia77 [94]
3 years ago
7

Would anyone pls help me on these questions Thanks

Physics
2 answers:
Karolina [17]3 years ago
5 0
Number 1 is 0, number 2 is moving, number 3 is Joules, number 4 is a thermometer, number 5 is gas, number 6 is more, number 7 is specific heat. Hope this was helpful
Alenkinab [10]3 years ago
3 0
1. 0°C
2. Motion
3. Joules
4. Thermometer
5. Gas
6. Less
7. Temperature
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What argument does Minow make in his speech?

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What do Ice core samples with lower ratios of O-18 to O-16 isotopes tell scientist about past climates
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Ocean-floor sediments can also be used to determine past climate. ... Ice cores contain more 16O than ocean water, so ice cores have a lower 18O/ 16O ratio than ocean water or ocean-floor sediments. Water containing the lighter isotope 16O evaporates more readily than 18O in the warmer subtropical regions

Explanation:

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How is silver, gold, and bronze different.
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Answer:

Silver is a malleable and ductile metal having atomic number 47 and symbol Ag. Gold on the hand has atomic number 79 and symbol Au. It is also ductile and malleable. Both are soft and lustrous in nature. Both are transition metals.

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Which is the following is a benefit of the water cycle to
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Can you complete the question...
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An aluminum wire is held between two clamps under zero tension at room temperature. Reducing the temperature, which results in a
Blababa [14]

Answer:

\frac{\Delta L}{L} =5.37\times 10^{-4}

Explanation:

Given:

  • cross sectional area of the wire, A=5.75\times 10^{-6}\ m^2
  • density of aluminium wire, \rho=2.7\times 10^3\ kg.m^{-3}
  • young's modulus of the material, E=7\times 10^{10}\ N.m^{-2}
  • wave speed, v=118\ m.s^{-1}

<u>We have mathematical expression for strain as:</u>

\frac{\Delta L}{L} =\frac{\sigma}{E} ...............................(1)

and since, \sigma =\frac{T}{A}

where, T = tension force in the wire

equation (1) becomes:

\frac{\Delta L}{L} =\frac{T}{A.E} ............................(2)

<u>Also velocity ofwave in tensed wire:</u>

v=\sqrt{\frac{T}{\mu} } ...................................(3)

where: \mu= linear mass density of the wire

\therefore \mu=\rho \times A

Now, equation (3) becomes

v=\sqrt{\frac{T}{\rho \times A} }

T=v^2.\rho \times A ............................(4)

Using eq. (2) & (4) for tension T

v^2.\rho \times A=A.E\times \frac{\Delta L}{L}

\frac{\Delta L}{L} =\frac{v^2.\rho}{E}

putting the respective values

\frac{\Delta L}{L} =\frac{118^2\times 2.7\times 10^3}{7\times 10^{10}}

\frac{\Delta L}{L} =5.37\times 10^{-4}

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3 years ago
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