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3 years ago

14

Batteries transform ______________ energy into mechanical energy.

2 answers:

alukav5142 [94]3 years ago

6 0

1. kinetic
2. not sure i think its a circut braker
3. no idea
4. i think a conductor
5. no idea

morpeh [17]3 years ago

3 0

Batteries transform "Chemical" <span>energy into mechanical energy.

A circuit breaker </span><span>of a circuit in a home is designed to be replaced if it stops a circuit overload

An Electrostatic force</span><span> causes the leaves in an electroscope to separate according to the law of charges.

</span><span>A material that conducts under certain conditions but acts as a resistor under other conditions is known as a "Semiconductor"

</span><span>Laser printers are one application of Static Electricity.
</span><span>
[bold letters are your answers]!
Hope this helps!

</span>

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Write whether true or false...

elixir [45]

Answer:

a --> true, b --> false, c --> true, d -->false

Explanation:

a) since it stays floating the gravity force and the upqards push is the same

b) if it's balanced the rocket won't move from the ground, the force of the rocket, has to exceed the force of gravity

c) since it's going in a diretion the force of gravity is exceeding the force pushing it up

d) since that are speeding up at a rate, meaning growing, the force is unbalanced.

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2 years ago

What is zero on the kelvin scale

elena55 [62]

The point at which all motion stops.

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3 years ago

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What physical feature of a wave is related to the depth of the wave base? What is the difference between the wave base and still

Inessa [10]

Answer:

physical feature of a wave is related to the depth of the wave base is The circular orbital motion

B. The wave base is the depth, and the still water level is the horizontal level

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2 years ago

An experiment is done to compare the initial speed of projectiles fired from high-performance catapults. The catapults are place

anzhelika [568]

Answer:1.084

Explanation:

Given

mass of Pendulum M=10 kg

mass of bullet m=5.5 gm

velocity of bullet u

After collision let say velocity is v

conserving momentum we get

$mu=(M+m)v$

$v=\frac{m}{M+m}\times u$

Conserving Energy for Pendulum

Kinetic Energy=Potential Energy

$\frac{(M+m)v^2}{2}=(M+m)gh$

here $h=L(1-\cos \theta )$ from diagram

therefore

$v=\sqrt{2gL(1-\cos \theta )}$

initial velocity in terms of v

$u=\frac{M+m}{m}\times \sqrt{2gL(1-\cos \theta )}$

For first case $\theta =6.8^{\circ}$

$u_1=\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}$

for second case $\theta =11.4^{\circ}$

$u_2=\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}$

Therefore $\frac{u_1}{u_2}=\frac{\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}}{\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}}$

$\frac{u_1}{u_2}=\frac{1819.181\times 0.0838}{1001\times 0.1404}$

$\frac{u_1}{u_2}=1.084$

i.e. $\frac{v_1}{v_2}=1.084$

4 0

3 years ago

Need an answer asap please!

olya-2409 [2.1K]

Answer:

Z

Explanation:

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3 years ago