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Llana [10]
2 years ago
6

Mila was given a large chocolate box for her birthday. If she eats exactly 3 chocolates each day, how many chocolates would Mila

have remaining 5 days after her birthday.
Mathematics
1 answer:
antoniya [11.8K]2 years ago
7 0
3*5=15, you didn’t specify how much chocolate was in the box, use the number of chocolate in the box and subtract it by 15, whatever number you get from that problem should be how much she’ll have remaining.
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Please solve the following question.
mylen [45]

Answer:

103, 776

Step-by-step explanation:

There are 48 possibilities, and you are picking 3.

Now, the order does matter (aka, if the same 3 athletes won but got different places, we would still consider it to be a separate possibility)

(this is considered "without repetitions")

the number of permutations (arrangement combinations where the order does matter) without repetitions formula:

Number of permutations

without <em>repetitions </em>= nPr

= \frac{n!}{(n-r)!}

(

[the P is for combinations [where the order does matter, if the order didn't matter then it would be C, and it would be a different formula.]

n is the total number of objects.

r is the number of objects selected]

<em>(a repetition would be like two versions of the same person competing, which doesn't make sense)</em>

{the ! means factorial:

5! = 5 x 4 x 3 x 2 x 1}

{for example, if there are 5 people to give a presentation, and they can go in any order [but cannot repeat their presentation], so they all must fill 5 slots}

{for the first slot there are 5 choices, the second slot there are 4 choices...}

)

So, if we follow this formula:

\frac{n!}{(n-r)!}

n: 48

r: 3

\frac{48!}{(48-3)!}

= \frac{48!}{45!}

=\frac{48 * 47*46*45!}{45!}

(the 45! cancel out)

= 48 * 47 * 46

= 103, 776

(or, without the formula:

for the first choice (lets say of gold), there are 48 options

for the second choice (lets say silver), there are 47 options left to choose from

for the third choice (lets say bronze), there are 46 options left to choose from

)

3 0
2 years ago
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
coldgirl [10]

Answer:

c is all the points in the open interval (0,25)

Step-by-step explanation:

Here given is a function

f(x) =x, which is continuous  in the interval [0,25] and differentiable in (0,25)

Mean value theorem says there exists at least one c in the interval (0,25) such that

f'(c) = \frac{f(25)-f(0)}{25-0}

We have

f(25)=25 and f(0) = 0\\f'(c) = 1

For the given function

f'(x) =1

Hence we have c equals all the points in the open interval (0,25)

7 0
3 years ago
Deandre wants to earn at least $30 trimming trees. He charges $7 per hour and pays $5 in equipment fees. What are the possible n
exis [7]
8 hours for the possible numbers of house
5 0
3 years ago
(07.02 MC)
BigorU [14]

Y=6 In this equation you also use combine like terms .

3 0
3 years ago
write the particular equation of this transformed sine graph. assume that the horizontal shift is 1 unit to the right. (hint: tr
Goryan [66]
We are given the graph of sine function.
First, we get the amplitude
A = [6 - (-2)] / 2
A = 4

Next, we determine the period and b
T = 4 - 0 = 4
b = 2π / T
b = π/2

The original sine function was
y = 4 sin πx/2

After the transformation, the equation now is
y = 4 sin [π(x+2)/2] + 2
4 0
3 years ago
Read 2 more answers
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