Answer:
The structures of all isomeric alcohols of molecular formula C5H12O along with their IUPAC names are as shown.
Their classification of primary, secondary, and tertiary alcohols are -
1-pentanol -
2-pentanol -
3-pentanol
2-methylbutan-1-ol
2-methylbutan-2-ol
3-methylbutan-2-ol
3-methylbutan-1-ol
2,2-dimethylpropanol
The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
According to half life equation:
T(1/2) = ㏑2 / K1
when the T(1/2) = 4 min * 60 = 240 sec
by substitution:
240 = 0.6931 / K1
K1 = 2.9 x 10^-3
when the second T(1/2) = 20 sec, so to get K2:
T(1/2) = 0.6931 / K2
by substitution:
20 = 0.6931 / K2
∴K2 = 3.4 x 10^-2
so, we can get T2 by using this formula:
㏑ (K2/K1) = Ea/R (1/T1 - 1/T2)
by substitution:
㏑(3.4 x 10^-2)/(2.9 x 10^-3) = (24520 / 8.314) (1/298 - 1/T2)
∴ T2 = 396.7 K
= 396.7 - 273 = 123.7 °C
<h3>
Answer:</h3>
Atoms of elements on the reactants side
- 2 Carbon atoms
- 6 Hydrogen atoms
- 7 Oxygen atoms
<h3>
Explanation:</h3>
- The equation; C₂H₅OH+ 3O₂ →2CO₂+ 3H₂O is balanced.
- A balanced chemical equation has an equal number of atoms of each element on either side of the equation.
- For example, in the equation given, the number of atoms of each element is equal on both sides of the equation.
- There are 2 carbon atoms, 6 hydrogen atoms, and 7 hydrogen atoms on either side of the equation.
- According to the law of conservation of mass, the mass of the reactants should be equal to the mass of reactants.
- Therefore, chemical equations are balanced for them to obey the law of conservation of mass.
<u>Answer:</u> The amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ
<u>Explanation:</u>
Endothermic reactions are defined as the reactions in which energy is absorbed in the reaction. The enthalpy change of the reaction is positive.
Exothermic reactions are defined as the reactions in which energy is released in the reaction. The enthalpy change of the reaction is negative.
For the given chemical equation:
In the above reaction, the enthalpy change is negative. So, the reaction is exothermic in nature.
For the reverse reaction, the magnitude of the enthalpy change remains the same but sign for it changes.
Hence, the amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ
