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-BARSIC- [3]
2 years ago
14

Just do these two problems for me and I’ll be so happy

Mathematics
1 answer:
Nady [450]2 years ago
7 0

Answer:

See below

Step-by-step explanation:

5) y = x + 7

6) y = -x + 1

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Directions:Use the product rule to simplify the following monomials.
abruzzese [7]

7) Answer = -24x^8y^{11}

\left(8x^4y^2\right)\left(-3x^4y^9\right)

=-8x^4y^2\cdot \:3x^4y^9

=-24x^4y^2x^4y^9

=-24x^8y^2y^9

=-24x^8y^{11}

8) Answer = -30y^6

2y\left(-5\right)y^2\cdot \:3y^3

=-30yy^2y^3

=-30y^{1+2+3}

=-30y^6

9) Answer = -6x^4y^5

\left(-2xy\right)\left(xy\right)\left(3x^2y^3\right)

=-2xyxy\cdot \:3x^2y^3

=-6xyxyx^2y^3

=-6x^4yyy^3

=-6x^4y^5

3 0
3 years ago
What is the slope of the line that represents this relationship?
galben [10]

Answer:

undefine

Step-by-step explanation:

the slope does not show rise over run it just sgow one of them therefore it is undefine

7 0
4 years ago
I need help on this question
rosijanka [135]

Answer:

11. Volume = 2181.2mm^3

12. Surface Area = 1204.49mm^2

Step-by-step explanation:

We first need to find the hypotenuse side of the triangle using the Pythagorean theorem:

a^2+b^2 = c^2

13.3^2+20.5^2 = c^2

176.89+420.25 = c^2

597.14 = c^2

24.44 = c

Now we can find the volume using the formula:

V = 1/4(16)sqrt-13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2

-20.5^4+2(20.5*24.44)^2-24.44^4

V = 2181.2mm^3

To find the surface area using the surface area formula:

A = (13.3*16)+(20.5*16)+(24.44*16)+1/2sqrt

13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2

-20.5^4+2(20.5*24.44)^2-24.44^4

A = 1204.49mm^2

7 0
3 years ago
If you answer all the questions on the picture I will give brainliest
Oduvanchick [21]

Answer:

1. 324

2. 610

3. 72

4. 97

5. 20

6. 28

7. 195

5 0
3 years ago
When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units
alexira [117]

Answer:

r=1/π

Step-by-step explanation:

Area of the circle is defined as:

Area = πr²

Derivating both sides

\frac{dA}{dr}=2πr

\frac{dA}{dt}  =  \frac{dA}{dr} x \frac{dr}{dt}  =  2πr\frac{dr}{dt}

If area of an expanding circle is increasing twice as fast as its radius in linear units. then we have : \frac{dA}{dt}  =2\frac{dr}{dt}

Therefore,

2πr \frac{dr}{dt}  =  2  \frac{dr}{dt}

r=1/π

5 0
3 years ago
Read 2 more answers
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