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2 years ago

I need help with this paper called Giving Circumference a Whirl for math

Mathematics

1 answer:

balu736 [363]2 years ago

5 0

Answer:

C = πd. where C is the circumference and d is the diameter of the circle. Using radius instead of diameter, the formula is: C = 2πr. where r is the radius of the circle.

Step-by-step explanation:

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What property is (3x+7)+(2x+8)=3x+7+2x+8

Alex_Xolod [135]

Answer:

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Step-by-step explanation:

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2 years ago

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

$= \dfrac{-1}{x(x+h)}, h\ne 0$

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3 years ago

If there is 15 liters of milk in the refrigerator, after how many days will more milk need to be purchased?

adoni [48]

Answer:

Depends on Howe much you can drink. It varies.

Step-by-step explanation:

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3 years ago