Answer: Weight only.
Explanation: Mass is a measure of the amount of matter in an object. Weight is a measure of the gravitational force exerted on the material in a gravitational field. Mass and weight are proportional to each other, with the acceleration due to gravity as the proportionality constant.
If a rock is transported from the moon to the earth, the mass is constant for the object but the weight will depends on the locations of the object. The gravitational acceleration would change because the radius and mass of the Moon is different from the Earth.
Thus, the object (rock) has <em>mass, m</em> both on the surface of the Earth and the surface of the Moon; but it will <em>weight</em> much less on the surface of the Moon as the Moon's surface gravity is 1/6 of the Earth.
Answer:
6 m/s
Explanation:
Velocity of Jake with respect to train = 4 m/s
velocity of train with respect to ground = 10 m/s
By the formula of relative velocity
velocity of Jake with respect to ground = 10 - 4 = 6 m/s
<h2>Answer </h2>
The kinetic energy is 8100 J.
<u>Explanation</u>
Mass is 50.0kg and velocity is 18 m/s, the kinetic energy is:
As we know the formula of kinetic energy which is K.E = ½ ( mv ^ 2 ),
mass = m = 50.0kg
velocity = v = 18 m / s,
by putting values in the formula,
K.E = ½ ( mv ^ 2 ),
K.E = ½ ( 50kg ) . ( 18 m / s ) ^ 2
K.E = ½ ( 50kg ) . ( 324 ),
=> K.E = 1/2 ( 16200 ),
=> K.E = 16200 / 2,
=> K.E = 8100J.
Hence, the kinetic energy ( K.E ) is 8100 joule ( J ).
Answer:
A. 80 N
Explanation:
Since the uniform plank is pivoted at its center at an angle of 30 to the vertical, then it is 90° - 30° = 60° to the horizontal.
Let L be the length of the plank = 4 m, the perpendicular distance of the 4 kg mass form the pivot point is Lcos60°/2. Then the moment of the 4 kg mass about its pivot point is mgLcos60/2 where m = mass = 4 kg and g = acceleration due to gravity = 10 m/s²
Let F be the force applied at 0.5 m from the pivot point. The perpendicular distance of F from the pivot point is 0.5cos60°. Thus the moment of this force about the pivot point is F × 0.5cos60° = 0.5Fcos60°
Since both moments are the same for equilibrium,
mgLcos60/2 = 0.5Fcos60°
F = mgL/(2 × 0.5 m)
F = 4 kg × 10 m/s² × 4 m/1 m
F = 80 kgm/s²
F = 80 N
Answer:
High-Level Clouds
Cloud types include: cirrus and cirrostratus.
High-level clouds form above 20,000 feet (6,000 meters) and since the temperatures are so cold at such high elevations, these clouds are primarily composed of ice crystals. High-level clouds are typically thin and white in appearance, but can appear in a magnificent array of colors when the sun is low on the horizon.
Mid-Level Clouds
Cloud types include: altocumulus, altostratus.
The bases of mid-level clouds typically appear between 6,500 to 20,000 feet (2,000 to 6,000 meters). Because of their lower altitudes, they are composed primarily of water droplets, however, they can also be composed of ice crystals when temperatures are cold enough.
Low-level Clouds
Cloud types include: nimbostratus and stratocumulus.
Low clouds are of mostly composed of water droplets since their bases generally lie below 6,500 feet (2,000 meters). However, when temperatures are cold enough, these clouds may also contain ice particles and snow.