The cost of going to a drive-in movie theater is $5. 50 per person plus $2. 75 per car. Use the dropdown menu to create an algeb
1 answer:
The algebraic equation which shows that the number of <em>x </em>people can go to the drive-in with one car for $19. 25 is,
Algebraic equation are the expression which consist the variables, coefficients of variables and constants.
The algebraic expression are used represent the general problem in the mathematical way to solve them.
Steps to write down the simple algebraic equation-
- Identify all the factors of the expression.
- Assume a variable for the changing values.
- Put a coefficient for the variable, if there is any rate of change of variable.
- Use constant numbers for the fixed values.
The cost of going to a drive-in movie theater is $5.50 per person plus $2.75 per car. It has to create an algebraic equation that shows how many people can go to the drive-in with one car for $19. 25.
Suppose the total number of people in the car for drive-in movie theater is <em>x</em>. Thus, the cost of the<em> </em><em>x</em> person to watch the movie is,
As the cost of one car is $2.75. Thus, the total cost of watching a movie by x person will be,
Now, the total cost, drive-in with one car for $19. 25. This cost must be equal to the above expression for total cost. Therefore,
Hence, the algebraic equation which shows that the number of <em>x </em>people can go to the drive-in with one car for $19. 25 is,
Learn more about the algebraic expression here;
You might be interested in
Step 2: She did not simplify under the square root correctly
under the square root:
(-6)^2 =36
and -4(5)(-8) =160
therefore under the square root it needs to be square root of 36+160 which is square root of 196.
That answer is 14 when square rooted
