Help me please
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THanks in advance ~
THanks in advance ~
2 answers:
<h3>#15</h3>
What elements forms electron rich hydride?
- <em>Electron</em><em> </em><em>rich</em><em> </em><em>hydride</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>only</em><em> </em><em>when</em><em> </em><em>the</em><em> </em><em>elements</em><em> </em><em>from</em><em> </em><em>group</em><em> </em><em>15-17</em><em> </em><em>combine</em><em> </em><em>together</em><em> </em><em>to</em><em> </em><em>form</em><em> </em><em>compounds</em><em>.</em><em>.</em><em>.</em>
Formula of Calgon is
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Answer : The mass of iron needed is 29.5 grams.
Explanation : Given,
Mass of = 12 g
Molar mass of = 32 g/mol
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 3 moles of react with 4 moles of
So, 0.375 mole of react with
mole of
Now we have to calculate the mass of
Molar mass of = 59 g/mole
Therefore, the mass of iron needed is 29.5 grams.