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Anon25 [30]
4 years ago
11

Someone please hellpp!!! Will mark brainliest

Physics
1 answer:
____ [38]4 years ago
6 0

<em>Answer:</em>

<em>r=x+y</em>

<em>sorry if its not correct you can delete if you want.</em>

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Nio conducts a science experiment. He puts yeast into a bottle with water and sugar, and then caps the bottle with a balloon. He
KATRIN_1 [288]

Answer: Option (C) is the correct answer.

Explanation:

When yeast is added into a bottle with water and sugar then after some time yeast becomes activated. This results in the formation of a chemical change as bubbles are formed on the surface of the mixture in the bottle.

This indicates that a gas has been released due to the chemical change.

Thus, we can conclude that most likely a chemical change has occurred because a gas was produced.

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4 years ago
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As more resistors are added in series across a constant voltage source, the power supplied by the source: A) does not change. B)
Anon25 [30]

As series resistors are added, the resistance is added directly so the total resistance will be equal to

R_T = R_1+R_2+R_3... R_{\infty}

Since the power is determined as

P = \frac{V^2}{R}

We have there that

P \propto \frac{1}{R}

The power is inversely proportional to the increase in resistance, so it will tend to decrease as more resistors are added in series.

The correct answer is: C.

4 0
3 years ago
Which of the following is an example of biotechnology?
anzhelika [568]
The short answer is a
3 0
3 years ago
A 2. 5 kg block is launched along the ground by a spring with a spring constant of 56 N/m. The spring is initially compressed 0.
OLga [1]

The speed of the spring when it is released is 3.5 m/s.

The given parameters:

  • <em>Mass of the block, m = 2.5 kg</em>
  • <em>Spring constant, k = 56 N/m</em>
  • <em>Extension of the spring, x = 0.75 m</em>

The speed of the spring when it is released is calculated by applying the principle of conservation of energy as follows;

K.E = U_x\\\\\frac{1}{2} mv^2 = \frac{1}{2} kx^2\\\\mv^2 = kx^2\\\\v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{56 \times 0.75^2}{2.5} } \\\\v = 3.5  \ m/s

Thus, the speed of the spring when it is released is 3.5 m/s.

Learn more about conservation of energy here:  brainly.com/question/166559

3 0
2 years ago
Read 2 more answers
Review. A bead slides without friction around a loop-the loop (Fig. P8.5). The bead is released from rest at a height h=3.50R (b
oksian1 [2.3K]

The normal force on the bead at point A is 1 N.

According to the Law Of Conservation of Energy, the total energy of the bead at the topmost point of height of 3.50 R is the same as its total energy at point A.

The energy at a height of 3.50R is equal to its potential energy which is

U= mgh= mg x 3.5R= 3.5mgR .........(i)

The energy at point A is,

E= mg(2R)+ 1/2 mv^2  ...........(ii)

Now, equating (i) and (ii)

3.5mgR = 2mgR + 1/2 mv^2

3.5mgR - 2mgR = 1/2mv^2

1.5gR = 1/2 v^2

3gR = v^2

V = √3gR

At point A, three forces are there weight of the bead(mg), normal reaction(N), and centripetal force(mv^2/r).

Balancing these forces,

mg + N = mv^2/r

N= mv^2/r - mg

Putting the given values in the above equation, we get the normal reaction

N= 1 N

Thus, the normal force on the bead at point A is 1N.

To know more about "Conservation of Mechanical Energy", refer to the following link:

brainly.com/question/11264649?referrer=searchResults

#SPJ4

8 0
1 year ago
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