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FrozenT [24]
2 years ago
11

Starting from rest, a racing car has a displacement of 201 m, S, in the first 5.0 s of uniform acceleration. What is the car's a

cceleration?
Physics
1 answer:
mihalych1998 [28]2 years ago
8 0

Answer:

Explanation:

s = ½at²

a = 2s/t²

a = 2(201) / 5.0²

a = 16.08

a = 16 m/s²

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Find the change in kinetic energy of a 0.650 kg fish leaping to the right at 15.0 m/s that collides inelastically with a 0.950 k
yaroslaw [1]
The change in the kinetic energy refers to the work done in displacing a body, thus, the change in the kinetic energy of an object refers to the work done on the object.
The correct formula to use is:
W = Initial kinetic energy - Final kinetic energy;
Where, W = change in kinetic energy
Final kinetic energy and initial kinetic energy = 1/2 MV^2
Initial velocity = 15 m/s
Final velocity  = 13.5 m/s
Initial mass = 0.650 kg
Final mass = 0.950 kg
W = 1/2 [0.650* (15 *15)] - 1/2 [0.950 * (13.5 * 13.5)]
W = 146.25 - 173.13 = 26.88
Therefore, the change in kinetic energy is 26.88 J.
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4 0
3 years ago
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andrey2020 [161]
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3 years ago
An uncrewed mission to the nearest star, Proxima Centauri, is launched from the Earth's surface as a projectile with an initial
Anna [14]

Answer:

42.96 km/s

Explanation:

From the conservation of Energy

(PE+KE)_i=(PE+KE)_f\\\Rightarrow -\frac{GmM}{R}+\frac{1}{2}mv_i^2=0+\frac{1}{2}mv_f^2

Mass gets cancelled

-\frac{GM}{R}+\frac{1}{2}v_i^2=0+\frac{1}{2}v_f^2\\\Rightarrow -2\frac{GM}{R}+v_i^2=v_f^2\\\Rightarrow -v_e^2+v_i^2=v_f^2\\\Rightarrow v_f=\sqrt{v_i^2-v_e^2}

v_e=\sqrt{\frac{2Gm}{R}} = Escape velocity of Earth = 11.2 km/s

v_i = Velocity of projectile = 44.4 km/s

v_f=\sqrt{44.4^2-11.2^2}\\\Rightarrow v_f=42.96\ km/s

The velocity of the spacecraft when it is more than halfway to the star is 42.96 km/s

6 0
3 years ago
The doppler effect is used to determine?
Korolek [52]
Uhh it is used to detirmine heat

7 0
3 years ago
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The vertical component of the projectile motion of an object depends on which of these? initial velocity or angel of trajectory
SVEN [57.7K]
It depends on both of them.

In fact, the projectile begins its motion with an initial velocity of v_0 and an angle of \alpha. On the y-axis (vertical direction), it is an accelerated motion with acceleration equal to -g (gravitational acceleration). The vertical velocity of the projectile at any time t is given by
v_y (t) = v_0 sin \alpha + gt
and as it can be seen, this depends on both initial velocity and angle.
3 0
3 years ago
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