Calculate the molarity of a solution prepared by dissolving 5.850g of solid NaCl in enough water to make 200mL of the solution?
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<u>Hydrogen bonds </u>are weak bonds that are not strong enough to hold atoms together to form molecules but are strong enough to form bonds within and around large molecules.
- The hydrogen bond is weak bond.
- The hydrogen bond is electrostatic force of attraction between hydrogen atom and more electronegative atoms or group ( like Florine , oxygen or nitrogen) which is contently bonded.
- The hydrogen bond is occur in polar , contently bond atoms in different molecules.
- Example is H-O-H or
- The positively charged hydrogen side of one water molecule is bond with negatively charged oxygen side of another molecule.
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Answer:-
Solution:- From given masses of carbon dioxide and water we could calculate the moles that helps to calculate the moles of C and H.
Molar mass of carbon dioxide = 44 gram per mol
molar mass of water = 18.02 gram per mol
From given info, combustion of compound gives 1.17 grams of water and 2.87 grams of carbon dioxide. Let's calculate the moles of these:
=
Similarly,
=
One mol of water has two moles of H. So, the moles of H would be two times the moles of water as calculated above.
So, moles of H = 2* 0.0649 = 0.1298 mol
One mol of carbon dioxide contains one mol of C. So, the moles of C would be equal to the moles of carbon dioxide calculated above.
moles of C = 0.0652 mol
Let's convert the moles of H and C to grams so that we could calculate the amount of oxygen present in the sample as:
grams of H in sample = 1.008 x 0.1298 = 0.1308 g
grams of C in sample = 12*0.0652 = 0.7824 g
If we subtract the sum of the masses of C and H from sample mass then it would give as the mass of oxygen since the sample has only C, H and O.
mass of O in sample = 3.00g - (0.1308 g + 0.7824 g)
= 3.00 g - 0.9132 g
= 2.0868 g
Let's convert these grams of oxygen to moles on dividing by it's atomic mass as:
= 0.130 mol O
Now, we have the moles of all the three atoms and we know that an empirical formula is the simplest whole number ratio of the moles of atoms. So, let's calculate the ratio. For this, we divide the moles of each by the least one of them.Looking at the moles, the least value is for carbon. So, let's divide the moles of each by the moles of C as:
C = = 1
H = = 2
O = = 2
The ratio of C, H and O is 1:2:2. So, the simplest formula of the compound is .