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sertanlavr [38]
3 years ago
10

Binary covalent compounds can be named as a function of what?

Chemistry
1 answer:
Luden [163]3 years ago
4 0

Answer:

Binary molecular (covalent) compounds are formed as the result of a reaction between two nonmetals.

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Is HBr a polar compound? Why or why not?
LenKa [72]
Yes, it is a Compound.

They both comprehend with the atoms of each sourse!
7 0
4 years ago
Read 2 more answers
In what area of the titration curve for phosphoric acid (h3po4) is the molecule fully deprotonated?
Arada [10]

The titration curve should have flat regions centered around each of the

three halfway points (buffer zones) and sharp increases in pH around the

equivalence points.

Initial pH

This is determined by the most acidic of the Ka values and the initial

concentration of the acid. (Same as a monoprotic acid)

Half-way points

At each halfway point, the pH = pKa of the group you are titrating. At this point in

the titration curve, we are in a buffering region, and the curve will be relatively

flat.

Equivalence points

At each equivalence point, the pH is the average of the pKa values above and

below. At the last equivalence point (the endpoint), the pH is determined by the

Kb of the conjugate base of the weakest acid.

Plotting the titration of 100 mL of 0.10 M phosphoric acid with 1.0 M NaOH.

H3PO4 + H2O  H2PO4

-

+ H3O+

Ka1 = 7.5 x 10-3

H2PO4

-

+ H2O  HPO4

2- + H3O+

Ka2 = 6.2 x 10-8

HPO4

2- + H2O  PO4

3- + H3O+

Ka3 = 4.2 x 10-13

Plot these points and connect them to determine the titration curve of phosphoric acid. The curve should be relatively flat around each of the halfway points when we are in a buffering region.

The titration curve should have flat regions centered around each of the

three halfway points (buffer zones) and sharp increases in pH around the

equivalence points.

For more information on the titration curve click on the link below:

brainly.com/question/3130161

#SPJ4

4 0
2 years ago
9. Calculate the standard enthalpy of the 3rd reaction using the given data: A,H° = +52.96 kJ/mol AFH= -483.64 kJ/mol H2s)+I202
Mice21 [21]

Answer:

-586.56 kJ/mol is the standard enthalpy of the 3rd reaction.

Explanation:

H_2(g) +I_2(s) \rightarrow 2 HI(g) ,\Delta H^{o}_{1}= +52.96 kJ/mol...[1]

2 H_2(g) + O_2(g)\rightarrow 2 H_2O(g),\Delta H^{o}_{2}=-483.64 kJ/mol...[2]

4 HI(g)+O_2(g)\rightarrow 2 I_2(s)+2 H_2O(g) ,\Delta H^{o}_{3} =?..[3]

The unknown standard enthalpy of third reaction can be calculated by using Hess's law:

The law states that 'the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps'.

[2] - 2 × [1] = [3]

O_2+4HI\rightarrow 2H_2O(g)+2I_2(s)

\Delta H^{o}_{3}=\Delta H^{o}_{2}-2\times \Delta H^{o}_{1}

=-483.64 kJ/mol - 2\times (52.96 kJ/mol)=-586.56 kJ/mol

The standard enthalpy of the 3rd reaction is -586.56 kJ/mol.The negative sign indicates that energy is released during this reaction.

6 0
4 years ago
The frequency of a given region of the electromagnetic spectrum ranges from
quester [9]
The ranges given are 4 × 10^14 to 7.5 × 10^14 Hz. At these frequencies, visible light type of waves are found in this region. This occurs at a wavelength of 400 - 700 nanometers and a color of violet through red. Outside this range, the naked eye cannot see the waves.
5 0
3 years ago
You want to clean a 500-ml flask that has been used to store a 0.9M solution. Each time the flask is emptied, 1.00 ml of solutio
Citrus2011 [14]

Answer:

In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M

Explanation:

In each rinse cycle, the dilution that you are doing of the solution is from 1.00mL to 10.00mL, that is a dilution of 10

In the first rinse the concentration must be of 0.9M  10 = 0.09M

2nd = 0.009M

3rd = 0.0009M

4th = 0.00009M

5th = 0.000009M →

<h3>In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M</h3>
4 0
3 years ago
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