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2 years ago

100PONITS!!!!!!!!!!!!!!!!

Mathematics

1 answer:

WARRIOR [948]2 years ago

7 0

Depends on how u look at the data and how the data is drawn out

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Lorenzo and his sister, Mariana, are decorating gingerbread houses. They want to make grass, so they turn their icing green by m

Alexandra [31]

Answer:

lorenzo

Step-by-step explanation:

because he has added more blue shade which will make the icing darker , Mariana's icing will be lighter as she added less blue shade :)

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2 years ago

Solve 2x – 11 = k for x.

Flura [38]

Answer:

First, you add 11 to the other side of the equals sign. So it would be 2x=k+11. Now, you divide 2 from x and do the same on the other side of the equals sign. so x= k+11

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Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Will mark brainliest

Harrizon [31]

Answer:

C : 0.167

Step-by-step explanation:

Have a nice day

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2 years ago

What is the domain and range of the relation shown in the table?

Leokris [45]

Answer:

domain: {-12, -8, 0, 1} range: {0, 8, 12}

Step-by-step explanation:

domain are of all the input values shown on the x-axis. The range is the set of possible output shown on the y-axis.

5 0

2 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

2 years ago