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melisa1 [442]
3 years ago
13

A typical circular saw has a radius of 0. 184 m and rotates so the velocity of its edge is 110 m/s. How many RPM does the saw ma

ke?
Physics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

[5710 RPM]

Explanation:

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Select all that apply. There MIGHT be more than one.
Stolb23 [73]
I believe the answer to your question is “Lithosphere plate boundaries”

The planet Earth is covered by a layer formed by land and rocks called the earth's crust or lithosphere. This crust is not smooth and uniform, but rather irregular and composed of tectonic plates, also called lithosphere plates. These plates are not fixed as they are under the magma (high temperature molten rock).

Hope this helps!:)
4 0
3 years ago
When the moon slowly moves away from the earth.How is it affecting the gravitational force between the earth and the moon?
sukhopar [10]
Well, think about how the tides will be affected when the moon moves farther away. If the moon first started off very close the earth, we would have more tsunamis. (Scientists have found that the moon has possibly been closer to earth long ago.) While it moves away, soon there will no longer be many tides.
3 0
3 years ago
What is the magnetic field strength required to make a proton with a speed of 5.0 x 10^(5) m/s follow a circular path of radius
Nuetrik [128]

Answer:

Magnetic field strength required for this is 0.25 T

Explanation:

As we know that the proton moves in circular path in uniform magnetic field

so the radius of the path of the circle is given as

R = \frac{mv}{qB}

here we know that

q = 1.6 \times 10^{-19}C

m = 1.6 \times 10^{-27} kg

R = 0.0200 m

v = 5 \times 10^5 m/s

now we have

B = \frac{1.6 \times 10^{-27} (5 \times 10^5)}{(1.6 \times 10^{-19})(0.02)}

so we have

B = 0.25 T

8 0
4 years ago
Water is flowing in a fire hose with a velocity of 1.0 m/s and a pressure of 200000 Pa. At the nozzle the pressure decreases to
jeka57 [31]

Answer:

The velocity is v_n  =14.09 \ m/s

Explanation:

From the question we are told that

    The velocity of the water in the pipe is  v_i =  1.0 \ m/s

     The pressure inside the pipe  is  P_i  = 200000 \ Pa

      The pressure at the nozzle is  P_n  =  101300 \ Pa

       The density of water is  \rho  =  1000 \ kg / m^3

      For the height h_1 = h_2 = h

where  h_1 is height of water in the pipe

  and  h_2 is height of water at the nozzle

Generally Bernoulli equation is represented as

       \frac{1}{2} \rho * v_i ^2 + \rho * g * h_1 +  P_i =  \frac{1}{2} \rho v_n ^2 + \rho * g* h_2 + P_n

=>   \frac{1}{2} \rho * v_i ^2 + \rho * g * h +  P_1 =  \frac{1}{2} \rho v_n ^2 + \rho * g* h + P_2

Where v_n is the velocity of the water at the nozzle

Now  making  v_n  the subject

            v_n  =  \sqrt{\frac{2}{\rho} [ P_i - Pn + \frac{1}{2} \rho v_i^2}

substituting values

            v_n  =  \sqrt{\frac{2}{1000} [ 200000 - 101300 + \frac{1}{2} (1000 * (1.0)^2)}

           v_n  =14.09 \ m/s

     

6 0
4 years ago
how much time would it take for an airplane to reach its destination if it traveled at an average speed of 790 kilometers/hours
igomit [66]

If the airplane covered 790 kilometers along the ground every hour,
and if it could keep that up, and if there was no wind, and if the
airplane pointed its nose directly toward its destination and never
zigged or zagged even the slightest bit, then it would cover
790 kilometers of the distance during the first hour, another
790 kilometers of the distance during the second hour, another
790 kilometers of the distance during the third hour, 790 more
kilometers of the distance during the fourth hour, and so forth
and so on until it had arrived at its destination.

The minimum time it would need for the total trip would be

           (4,700 kilometers) / (790 kilometers per hour) =

                               5.9494... hours (rounded)

                           5hours 56m  57.7seconds  (rounded) .

(790 kilometers) x (1 mile / 1.609344 kilometers) =  490.88 miles (rounded)

8 0
3 years ago
Read 2 more answers
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