The net force on the larger mass in the horizontal direction (where we take the direction of F to be positive) is
F - T = 2Ma
where T is the magnitude of tension and a is the mass's acceleration.
The net force on the smaller mass in the vertical direction (upward is positive) is
T - Mg = Ma
If M = 1.0 kg and F = 60 N, then we end up with two equations with two unknowns,
60 N - T = (2.0 kg) a
T - (1.0 kg) (9.8 m/s²) = (1.0 kg) a
Eliminate a and solve for T :
(60 N - T) - 2 (T - (1.0 kg) (9.8 m/s²)) = (2.0 kg) a - 2 (1.0 kg) a
60 N - T - 2T + 19.6 N = (2.0 kg) a - (2.0 kg) a
40.4 N - 3T = 0
3T = 40.4 N
T = (40.4 N) / 3
T ≈ 13 N
Answer: Some challenges that I could see would be the walls, possibly a moat, tar, and the towers.
Explanation: The wall is obliviously a main problem, trying to get over it or through it is a difficult challenge. The moat (if it has one) means that there is more than likely only one way to get in or out. If it does have tar it means that the attackers are going to be put in a "sticky situation" And finally the towers, they have people at the top shooting arrows down at you, or throwing things at you.
Answer:
Mar's orbital path is more than that of Earth, thus it takes more number of days to orbit around the sun.
Explanation:
Mars takes over 500 days to orbit all the way around the sun than Earth because its distance from the sun (228 million kilometers) is greater than that of Earth (150 million kilometers) which takes it 365 days.
Planets that orbit closer to the sun take shorter time to orbit around the sun because the cover a shorter orbital distance and orbit faster than those planets further from the sun.
<u>For example</u>
Using Earth's distance from the sun, 150 million kilometers and the number of days taken to orbits the sun ,365 days and the distance Mars is from the Earth, 228 million kilometers, you can approximate the time Mar takes to orbit the sun as:
Earth 150 million kilometers = 365 days
Mars 228 million kilometers= ?
Cross product ; (228 *365) /150 =555 -----(a value closer to that in the question)
Answer:
<em>There will be an increase in potential difference.</em>
Explanation:
As we know that the potential difference depends upon the capacitance.
ΔV = Q/C
When battery is disconnected the charge remains constant on the plates but the capacitance decreases. As the capacitance has an inverse relation with the potential difference, there will be an increase in it.
In addition to that the potential difference can also be defined as the product of field and distance between the plates. As the charge is constant so the field is constant. Upon increasing the separation between the plates the potential difference will also increased.
Answer:
De cual Tema??? jajaja no se que necesitas
