At what distance must a star be to have its apparent magnitude equal to its absolute magnitude?

1 answer:

6 0

10 parsecs<span>Another way to look at this is that the apparent magnitude (brightness from true distance) is brighter than the absolute magnitude (brightness from 10 parsecsaway). So Ross 128 must be closer than 10 parsecs, making star look brighter than it "really" is.</span>

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An electron has a constant acceleration of +3.3 m/s2. at a certain instant its velocity is +8.6 m/s. what is its velocity (a) 2.

Citrus2011 [14]

Hello!

The velocity function is:

$\mathsf{V = V_0 + at}\\ \\ \mathsf{V = 8.6 +3.3t}$

a) 2.3 s earlier, we can make t = -2.3 s, in relation to our initial time:

$\mathsf{V = 8.6 + 3.3\cdot(-2.3)}\\ \\ \mathsf{V = 8.8-7.59}\\ \\ \boxed{\mathsf{V = 1.21 \ m/s}}$

b) Now we can make t = 2.3 s:

$\mathsf{V = 8.6 + 3.3\cdot2.3}\\ \\ \mathsf{V = 8.6 + 7.59}\\ \\ \boxed{\mathsf{V = 15.59 \ m/s}}$

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kirza4 [7]

Answer:

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