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Margaret [11]
3 years ago
13

1. During the Middle Ages, armies often attacked castles using large siege engines such as the counterweight trebuchet at left.

What challenges might you face if you attacked a castle?
Physics
1 answer:
fredd [130]3 years ago
8 0

Answer: Some challenges that I could see would be the walls, possibly a moat, tar, and the towers.

Explanation: The wall is obliviously a main problem, trying to get over it or through it is a difficult challenge. The moat (if it has one) means that there is more than likely only one way to get in or out.  If it does have tar it means that the attackers are going to be put in a "sticky situation" And finally the towers, they have people at the top shooting arrows down at you, or throwing things at you.

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Hi Guys.I was just wondering if given two specific heat capacities (In my case copper and water) do you add them both together o
timama [110]

Answer:

yes

Explanation:

using law of HC(heat capacity), which is

  • heat loss=heat gain
  • energy H=MCQ

Where M is mass of substance,C is specific heat capacity, and Q is temperature change

In case of two substance

  • the H = Mc*Cc*Q+Mw*Cw*Q(provided the initial and final temperature are given)

8 0
3 years ago
A light spring obeys Hooke's law. The spring's unstretched length is 33.5 cm. One end of the spring is attached to the top of a
ZanzabumX [31]

Answer:

807.88N/m

Explanation:

<em>The  question has some missing details in it, nevertheless, based on the given data we want to find the spring constant K</em>

Step one

given data

Unstretched length = 33.5 cm

Final length of the spring = 42.0 cm

Δx= 42-33.5

Δx=8.5cm to m= 0.085m

mass m= 7kg

The force on the spring

F=mg

F= 7*9.81

F=68.67N

Step two:

From Hooke's law, we can make k subject of formula and find the spring constant k, we have

F=kΔx---------1

make k subject of the formula

k=F/Δx

k= 68.67/ 0.085

k=807.88N/m

4 0
3 years ago
A light source of wavelength \lambdaλ illuminates a metal with a work function of \text{BE} = 2.00 ~\text{eV}BE=2.00 eV and ejec
dsp73

Answer:

1 eV

Explanation:

Given:

Work function, ∅ = 2.00 eV

Kinetic energy of the ejected of the electron, K.E = 4.0 eV

Now,

using the photoelectric equation , we have

Energy of the photon (E) = ∅ + K.E

also,

E = hc/λ

where, h is plank's constant

c is the speed of the light

λ is the wavelength

thus, we have

hc/λ = 2 + 4 = 6 eV

Energy of photon = 6eV

Now,

for the second case

λ' = 2λ

when Wavelength is doubled , E is halved

thus,

E' = hc/λ'

or

E' = hc/2λ

or

E' = E/2 = 6/2 = 3 eV

also,

E' = ∅ + KE '

thus on substituting the values,

3 = 2 + KE'

or

KE' = 1 eV

Hence, the maximum kinetic energy for the second case is 1 eV

5 0
3 years ago
A pendulum has 895 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
LuckyWell [14K]

Newton's law of conservation states that energy of an isolated system  remains a constant. It can neither be created nor destroyed but can be transformed  from one form to the other.

Implying the above law of conservation of energy in the case of pendulum we can conclude that at the bottom of the swing the entire potential energy gets converted to kinetic energy. Also the potential energy is zero at this point.

Mathematically also potential energy is represented as

Potential energy= mgh

Where m is the mass of the pendulum.

g is the acceleration due to gravity

h is the height from the bottom z the ground.

At the bottom of the swing,the height is zero, hence the potential energy is also zero.

The kinetic energy is represented mathematically as

Kinetic energy= 1/2 mv^2

Where m is the mass of the pendulum

v is the velocity of the pendulum

At the bottom the pendulum has the maximum velocity. Hence the kinetic energy is maximum at the bottom.

Also as it has been mentioned energy can neither be created nor destroyed hence the entire potential energy is converted to kinetic energy at the bottom and would be equivalent to 895 J.

7 0
4 years ago
Each of the four expansion models (recollapsing, critical, coasting, and accelerating) predict different ages for the universe,
cupoosta [38]

Answer:

This is because the age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

Explanation:

The age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

This is due to the fact that the expansion rate in the coasting model is constant and never changes. Because the cosmos is growing faster now than during the old days, recollapsing and critical models give shorter ages. According to the accelerating model, the universe is growing at a slower rate currently than in the past, implying an older age.

4 0
3 years ago
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