2 years ago

Running with an initial velocity of +11 m/s, a horse has an average acceleration of -1.8

Physics

1 answer:

dexar [7]2 years ago

5 0

Answer:

t = 2.5 seconds

Explanation:

We know the relation :

v = u + at

6.5 = 11 - 1.8t

=> 1.8t = 4.5

=> t = 4.5/1.8

=> t = 2.5 seconds

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When waves enter a denser medium, they bend the normal.<br><br> A) Toward<br> B) Away From

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The answer is bend towards normal.

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Two automobiles traveling at right angles to each other collide and stick together. Car A has a mass of 1200 kg and had a speed

sergij07 [2.7K]

Answer:

$v_{B0}=15.73 m/s$

Explanation:

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y-coordinate

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We can divide equations (2) and (1):

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$\frac{m_{B}v_{B0}}{m_{A}v_{A0}}=tan(40)$

$v_{B0}=\frac{m_{A}v_{A0}}{m_{B}}*tan(40)$

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I hope it helps you!

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3 years ago

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4025.05m +20.0m +0.050004m

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The answer is 4,045.1 meters

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3 years ago

If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in m

algol [13]

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

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Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

$H=ut+\dfrac{1}{2}at^2$

Here, a = g

$H=\dfrac{1}{2}gt^2$

$H=\dfrac{1}{2}\times 9.8\times (2.261)^2$

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

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3 years ago