F(x)=-5x+1x=−5x+1, find f(6)

Mathematics

1 answer:

vaieri [72.5K]3 years ago

3 0

Answer:

f(x)=-5x+1x=−5x+1, find f(6)

f(6)= -5(6)+1(6)=-5(6)+1

F(6)=-24,-29

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A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.

Papessa [141]

Answer:

$\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}$

Step-by-step explanation:

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

$\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}$

$\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }$

<h3>Hence the number of cubes that can be fitted in the box is 60 .</h3>

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3 years ago

Pls help me with this question

RoseWind [281]

Answer:

the answer is 3 and 90 that's all

8 0

2 years ago

Read 2 more answers

Solve for a: a(a-3) =100

marissa [1.9K]

$a(a-3) =100\\
a^2-3a-100=0\\
\Delta=(-3)^2-4\cdot1\cdot(-100)=9+400=409\\
\sqrt{\Delta}=\sqr{409}\\
a_1=\dfrac{-(-3)-\sqrt{409}}{2\cdot1}=\dfrac{3-\sqrt{409}}{2}\\
a_2=\dfrac{-(-3)+\sqrt{409}}{2\cdot1}=\dfrac{3+\sqrt{409}}{2}$