compare the triangles ΔABC and ΔBCD
∡ABC = ∡BCD (given)
AB = CD (given)
BC = BC (common) } = > (SAS) ΔABC ≡ ΔBCD = > AC = BD
Answer:
see below
Step-by-step explanation:
3x^2 + 17x +10 =0
(3x+ ) ( x+ ) =0
We need to factor 10 = 2*5 or 1*10
They are positive since we have all positive terms
3*5 = 15+2 = 17
The 5 needs to multiply the 3 so it goes on the outside
(3x+ ) ( x+ 5 ) =0
That leaves the 2 on the inside
(3x+ 2 ) ( x+ 5 ) =0
Using the zero product property
3x+2 =0 x+5=0
3x = -2 x=-5
x = -2/3 x = -5
First off, let's convert 0.25 to a fraction, notice, it has two decimals, therefore, we'll use two zeros on the denominator, two decimals, two zeros, thus,
Answer:
C 16x-2+y
Step-by-step explanation:
we can split this into 3 terms with common denominator 3
48x/3 -6/3 + 3y/3
now divide each term
16x-2+y
12 devided by 4 is 12Step-by-step explanation:
