Answer:
Accelerate up more compressed spring
Accelerate down spring less compressed
Explanation:
For this problem we must analyze the forces that act on the scale on the one hand the weight of the man directed downwards and I have the other the elastic force of the spring directed upwards. Now let's write Newton's second law for these forces in various configurations,
When the elevator is quiet or moving at constant speed
Fe - W = 0 ⇒ Fe = W -k x = mg x = mg /k
Fe = mg
We use this value to compare
Now let's analyze when the elevator accelerates upwards
Fe -W = m a
Fe = ma + W
Fe = m (a + g)
So we can see that Fe increases, so the compression of springs is higher
Now let's analyze when the elevator acceleration is down
Fe -W = m (-a)
Fe = w - m a
Fe = m (g -a)
In this case Fe is smaller, so the compression of the spring is less
Answer:
The speed of the combined vehicles is 6.82m/s
Explanation:
Using the law of conservation of momentum which stayed that the sum of momentum of bodies before collision is equal to their sum of momentum after collision. After collision, both object moves with the same velocity.
Momentum = mass×velocity
Before collision:
Momentum of vehicle or mass 3000kg moving with velocity 25m/s
= 3000×25
= 75000kgm/s
Pa = 75000kgm/s
Momentum of vehicle with mass 2500kg moving with velocity of -15m/s
= 2500×-15
= -37500kgm/s
After collision:
Momentum = (3000+2500)V
Where v is their common velocity
Momentum after collision = 5500V
Based on the law:
75000+(-37500) = 5500V
75000-37500 = 5500V
37500 = 5500V
V = 37500/5500
V = 6.82m/s
Answer:
450 × 10 ⁻⁹ N
Explanation:
From the given:
The direction of force is;
Hence, the angle is 45° counterclockwise from + x-axis
However;
the magnitude of the force is:
Answer:
32500N
Explanation:
Data obtained from the question include:
m (mass) = 2500 kg
a (acceleration) = 13 m/s2
F (force) =?
Force is the product of mass and acceleration. It is represented mathematically as:
Force = mass x acceleration
F = m x a
With the above formula, the force with which the car strikes the barrier can be obtained as follow:
F = m x a
F = 2500 x 13
F = 32500N
Therefore, the car will strike the barrier with a force of 32500N
Answer:
Weather situations can be prepared for in many cases,
Explanation:
