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2 years ago

Question 1 of 10

Physics

1 answer:

Debora [2.8K]2 years ago

7 0

Answer:

V = λ f (wavelength * frequency)

λ = V / f = 343 m/s / 262 / s = 1.3 m

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An imaginary line perpendicular to a reflecting surface is called ____refrac_____.

umka2103 [35]

Not totally sure but i would say a normal? its not refraction or incidence if its perpendicular and i dont think its a mirror if its an imaginary line so yeah normal (normals are always perpendicular to their surface too i think so)

4 0

3 years ago

A psychopathologist records the number of criminal offenses among teenage drug users in a nationwide sample of 1,201 participant

lara [203]

Answer:

Standard deviation = 3

Explanation:

Given

$N = 1201$

$SS = 10800$

Required

Determine the standard deviation

First, we need to determine the variance;

$Variance = \frac{SS}{N - 1}$

This gives:

$Variance = \frac{10800}{1201 - 1}$

$Variance = \frac{10800}{1200}$

$Variance = 9$

Know that:

$Variance = SD^2$

Where SD represents standard deviation

This gives

$9 = SD^2$

Take square root

$SD = \sqrt 9$

$SD = 3$

7 0

3 years ago

Describe the tide requirements necessary to create a tidal power plant.

spin [16.1K]

Answer:

La energía mareomotriz se produce gracias al movimiento generado por las mareas, esta energía es aprovechada por turbinas, las cuales a su vez mueven la mecánica de un alternador que genera energía eléctrica, finalmente este último esta conectado con una central en tierra que distribuye la energía hacia la comunidad.

6 0

3 years ago

John pushes a box with a constant force as shown in the graph below.

andrew11 [14]

From the graph, it can be seen that the constant force that John exerted in order to move the object is 14N. Work is calculated by multiplying the force with the distance to which the object moves in parallel with the direction of the force.
Work = Force x displacement
Work = (14 N) x (8 m)
Work = 112 J
The closest value is 110J. Thus, the answer to this item is the second choice.

4 0

3 years ago

An object of mass 300 g, moving with an initial velocity of 5.00i-3.20j m/s, collides with an sticks to an object of mass 400 g,

Alexus [3.1K]

Answer:

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

Explanation:

Mass of object 1 , m₁ = 300 g = 0.3 kg

Mass of object 2 , m₂ = 400 g = 0.4 kg

Initial velocity of object 1 , v₁ = 5.00i-3.20j m/s

Initial velocity of object 2 , v₂ = 3.00j m/s

Mass of composite = 0.7 kg

We need to find final velocity of composite.

Here momentum is conserved.

Initial momentum = Final momentum

Initial momentum = 0.3 x (5.00i-3.20j) + 0.4 x 3.00j = 1.5 i + 0.24 j kgm/s

Final momentum = 0.7 x v = 0.7v kgm/s

Comparing

1.5 i + 0.24 j = 0.7v

v = 2.14 i + 0.34 j

Magnitude of velocity

$v=\sqrt{2.14^2+0.34^2}=2.17m/s$

Direction,

$\theta =tan^{-1}\left ( \frac{0.34}{2.14}\right )=9.03^0$

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

7 0

3 years ago