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2 years ago

Brainliest if correct Question 4 of 10

Physics

1 answer:

seraphim [82]2 years ago

3 0

Answer:

E is the answer of the question in my opinion

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Can an objects displacement be greater than or equal to the objects distance?

Reptile [31]

If you say displacement is greater than distance, you will contradict the above statement. Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector.So' displacement cannot be more than distance.

6 0

4 years ago

How do you find the voltage of a section of a parallel circuit?

sergiy2304 [10]

Answer: Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source. You can find total resistance in a Parallel circuit with the following formula: 1/Rt = 1/R1 + 1/R2 + 1/R3 +.

Hope this helps!

3 0

4 years ago

During normal beating, the heart creates a maximum 3.60 mV potential across 0.250 m of a person's chest, creating a 1.00 Hz elec

grandymaker [24]

Answer:

The maximum electric field strength is 0.0144 V/m.

Explanation:

Given that,

Electric potential created in the heart, V = 3.6 mV

Distance, d= 0.25 m

Frequency of the the electromagnetic wave, f = 1 Hz

We need to find the maximum electric field strength created. We know that the electric potential is given by :

$V=Ed$

E is the maximum electric field strength

$E=\dfrac{V}{d}\\\\E=\dfrac{3.6\times 10^{-3}\ V}{0.25\ m}\\\\E=0.0144\ V/m$

So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.

5 0

3 years ago

If a sample of a radioactive isotope has a half-life of 1 year, how much of the original sample will be left at the end of the s

Tasya [4]

Answer:

1/4 of the original

Explanation:

That would be TWO half lives:

1/2 * 1/2 = 1/4 <======= 1/4 would be left

4 0

1 year ago

Light shines through a single slit whose width is 5.6 × 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a

Mrac [35]

Answer:

462 nm

Explanation:

Given: width of the slit, d = 5.6 × 10⁻⁴ m

Distance of the screen, D = 4.0 m

Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m

First dark fringe means n =1

Wavelength of the light, λ = ?

$\beta = \frac{\lambda D}{d}\\ \Rightarrow \lambda = \frac{d \beta}{D} =\frac{5.6\times 10^{-4} \times 3.3 \times 10^{-3}}{4.0} = 4.62 \times 10^{-7}m = 462 nm$

5 0

3 years ago