Add the reltive atomic mass of Ca and O which are 40 and 16 respectively after addition we get molecular mass of CaO which is 40+16=56 now divide atomic mass of O by molecular mass of CaO and multiply it with 100 as show n 16/56 *100=28.57%
Answer:
Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F
Explanation:
At the given interval, concentration of HI = 
Concentration of 
= 
Concentration of 
= 
Reaction quotient,
, for this reaction = ![\frac{[H_{2}][I_{2}]}{[HI]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5BI_%7B2%7D%5D%7D%7B%5BHI%5D%5E%7B2%7D%7D)
species inside third bracket represents concentrations at the given interval.
So, 
So, the reaction is not at equilibrium.
As 
therefore reaction must run in reverse direction to reduce and make it equal to 
. That means HI(g) must be produced and must be consumed.
The density of the rock is 3.314g/mL
CALCULATE DENSITY:
- According to this question, a rock weighs 23.2g. After dropping the rock into a graduated cylinder containing 55mL of water, the level changes to 62mL.
- This means that the volume of the rock can be calculated as follows:
Volume of rock = 62mL - 55mL
Volume of rock = 7mL
Density can be calculated using the formula as follows:
Density = mass ÷ volume
Density = 23.2 ÷ 7
Density = 3.314g/mL
Therefore, the density of the rock is 3.314g/mL
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