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adoni [48]
3 years ago
5

Is kicking a ball or throwing a ball considered applied force? Explain.

Physics
1 answer:
Aliun [14]3 years ago
6 0

Answer:

Kicking a ball involves you applying a force because you are pushing it with your foot and that makes it fly up. Once you shoot something into the air, the gravity force pulls it back down to the Earth, which is a different type of force.

Explanation:

hope this helps :)

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On a spacecraft, two engines are turned on for 684 s at a moment when the velocity of the craft has x and y components of v0x 43
Natasha2012 [34]

As we know by the kinematics

\delta x = v_x * t + \frac{1}{2} at^2

4.11106 = 4370* 684 + \frac{1}{2}a_x*684^2

4.11106 = 2989080 + 233928*a_x

a_x = -12.78 m/s^2

Similarly for Y direction

\delta y = v_y * t + \frac{1}{2} at^2

6.07106 = 6280* 684 + \frac{1}{2}a_y*684^2

6.07106 = 4295520 + 233928*a_y

a_y = -18.36 m/s^2

8 0
3 years ago
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When entering an expressway, in the acceleration lane you should: A search for a gap in traffic and adjust your speed to the spe
sattari [20]

Answer:A

Explanation: search for a gap in traffic and adjust your speed to the speed of the traffic.

3 0
3 years ago
Two cars are driving at the same constant speed on a straight road, with car 1 in front of car 2. car 1 suddenly starts to brake
Ganezh [65]
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4 0
4 years ago
. Take a stick of length one and denote it by the unit interval [0, 1]. Pick two i.i.d. Uniform(0, 1) random variables U and V a
BartSMP [9]

Answer:

What is the expected value of L = 1/3

Explanation:

kindly check the attached file below.

5 0
4 years ago
HELPPPPP !!!!
Nataly [62]

Your answer is C)

a)t=2.78 sec

b)R=835.03 m

c)

Explanation:

Given that

h= 38 m

u=300 m/s

here given that

The finally y=0

So

t=2.78 sec

The horizontal distance,R

R= u x t

R=300 x 2.78

R=835.03 m

The vertical component of velocity before the strike

4 0
3 years ago
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