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maria [59]
3 years ago
12

Two cars are driving at the same constant speed on a straight road, with car 1 in front of car 2. car 1 suddenly starts to brake

with constant acceleration and stops in 10 m. at the instant car 1 comes to a stop, car 2 begins to brake with the same acceleration. it comes to a halt just as it reaches the back of car 1. what was the separation between the cars before they starting braking?
Physics
1 answer:
Ganezh [65]3 years ago
4 0
<span> Maths delivers! Braking distance ... If the </span>car<span> is initially travelling at u</span>m<span>/s, then the stopping distance d </span>m<span> ... the </span>speed<span> of the </span>car<span> at the </span>instant<span> the </span>brakes<span> are applied. ... An object with </span>constant acceleration<span> travels the </span>same<span> distance as it would ... We </span>start<span> with the second equation of motion:.</span>
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Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 23.5 m above water wit
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As stated in the statement, we will apply energy conservation to solve this problem.

From this concept we know that the kinetic energy gained is equivalent to the potential energy lost and vice versa. Mathematically said equilibrium can be expressed as

\Delta KE = \Delta PE

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Where,

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As the mass is tHe same and the final height is zero we have that the expression is now:

\frac{1}{2}v_f^2-\frac{1}{2} v_0^2 = gh_2

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v_f = \sqrt{2gh_2+v_0^2}

v_f = \sqrt{2(9.8)(23.5)+13.6^2}

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What is the force needed to give a .25 kg arrow an acceleration of 196m/s2?
Rzqust [24]
<span>49N is the force needed to give a .25 kg arrow an acceleration of 196m/s2. F =ma ⇒ =( 0.25kg)(196m/s2) = 49N if the arrow is shot horizontally where the applied force is entirely in the x-direction.</span>
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A car has an acceleration of 1.5 m/s2. A net force of 2100 N is acting on the car. What is the mass of the car?
gulaghasi [49]

Answer:

Given

acceleration (a) =1.5ms2

Force(F) =2100N

R. t. c mass (m) =?

Form

F=ma(divided by m both sides)

m=F/a

m=2100/105

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Where are the factors ... to this question

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nciado: Frequentemente, em ciências exatas, utilizamos potências de base 10 para expressar números muito grandes ou muito pequen
Mariulka [41]
Hi. The language here looks as though it's Spanish/Portugese ??? It would help to answer the q if the q were posted in english. I speak a little spanish and french, but it's mostly guesswork.
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