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maria [59]
4 years ago
12

Two cars are driving at the same constant speed on a straight road, with car 1 in front of car 2. car 1 suddenly starts to brake

with constant acceleration and stops in 10 m. at the instant car 1 comes to a stop, car 2 begins to brake with the same acceleration. it comes to a halt just as it reaches the back of car 1. what was the separation between the cars before they starting braking?
Physics
1 answer:
Ganezh [65]4 years ago
4 0
<span> Maths delivers! Braking distance ... If the </span>car<span> is initially travelling at u</span>m<span>/s, then the stopping distance d </span>m<span> ... the </span>speed<span> of the </span>car<span> at the </span>instant<span> the </span>brakes<span> are applied. ... An object with </span>constant acceleration<span> travels the </span>same<span> distance as it would ... We </span>start<span> with the second equation of motion:.</span>
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The equation shows neutralization of an acid and a base to produce a salt and water.
Masja [62]

The answer is; 2.

To balance a chemical equation, the moles on one side of the equation has to be the same as that on the other side. This ensures that the law of conservation  is observed because matter or energy can't be created or destroyed but can only be transformed from one form to another.

In this equation, putting 2 in front of NaCl ensures that there are 2 moles of Na and CL just as there are 2 moles of Na and CL in the reactants side.


6 0
3 years ago
Read 2 more answers
A mass of 100kg is acted on by a 400N force acting vertically upward and a 600N force acting at a 45 degrees angle.Calculate the
slava [35]

Answer:

A 1.56    see below

Explanation:

I will assume the 45 degree force is upward

vertical component =   600 sin 45 = 424.26 N

 added to the other vertical force will total 824.26 N

    F = ma

   824.26 = 100 * a    shows a = 8.24 m/s upward

Now we have to assume the mass is ALSO acted on by gravity and this value is given as  9.8  ( so downward is positive)

9.81 -   8.24      =  1.56 m/s^2

8 0
2 years ago
Describe the structure and layers of the sun. the layer of the sun is in three equally side the sun the moon and the galaxy
Greeley [361]
I’m so glad that I can help with this
4 0
3 years ago
The First Law of Thermodynamics is the same as ______ with heat and work taken into consideration.
Dafna1 [17]

Answer:

the law of conservation of energy

3 0
3 years ago
g A uniform ladder whose length is 4.4 m and whose weight is 330 N leans against a frictionless vertical wall. The coefficient o
Damm [24]

Answer:

Distance = 4.4 [m]

Explanation:

This problem can be easily solved using a static analysis of forces acting on the ladder, taking into account the respective distances. For easy understanding, a free body diagram should be made.

We perform a sum of force on the X-axis equal to zero, to find that the force exerted by the wall is equal to the friction force on the floor.

Then we perform a summation of forces on the Y axis, to determine that the normal force exerted by the floor is equal to the weight of the ladder.

We know that the friction force is equal to the product of normal force by the coefficient of friction.

In this way, by relating the friction force to the equations deduced above we can find the force exerted by the wall.

Then we make a summation of moments around the base point of the ladder, the equation realized can be seen in the attached image.

In the last analysis we can find the relationship between the horizontal and vertical distance of the ladder, with respect to the wall and the floor.

Then with the complementary analysis of the Pythagorean theorem we can find another additional equation.

The result of the greater distance is 4.4 [m]

3 0
3 years ago
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