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Lina20 [59]
2 years ago
11

What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450. 0 mL solution? (Hint:

must convert grams to moles first).
Chemistry
1 answer:
Salsk061 [2.6K]2 years ago
4 0

Molarity is the molar concentration of the solute dissolved in a volume of a solution. The molarity of the solution prepared by dissolving barium chloride will be 0.085 M.

<h3>What is molarity?</h3>

Molarity is the ratio of the moles of the solute to that of the volume of the solution in Liters. It can be given as,

\rm Molarity = \dfrac{moles}{Volume}

Here, moles of the barium chloride can be given by the mass and the molar mass and volume is given as 0.450 L.

Substituting values in the equation:

\begin{aligned}\rm Molarity &= \rm \dfrac{mass}{Molar \;mass\times Volume}\\\\&= \dfrac{8}{208.23\times 0.450}\\\\&= 0.085\;\rm M\end{aligned}

Therefore, 0.085 M barium chloride is the molar concentration.

Learn more about molarity here:

brainly.com/question/26873446

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Nearly every compound of silicon has the element in the ⁺4 oxidation state. In contrast, most compounds of lead have the element
baherus [9]

Boron shows analogous behaviour with silicon. Every compound of Boron have +3 oxidation state, while as we go down the the oxidation state become +1 and +3. For example, gallium, indium, etc.

Similarly, every compound of silicon has the element in the ⁺4 oxidation state. In contrast, most compounds of lead have the element in the ⁺2 state because of inert pair effect.

<h3>What is Inert pair effect? </h3>

The inert-pair effect is defined as the tendency of two electrons in the outermost atomic s-orbital almost remain unshared in the compounds of the post-transition metals.

<h3>How we calculate Oxidation state? </h3>
  • Each atom in an element either be in its uncombined or free state has oxidation number of zero. Such as each atom in H₂, Cl₂ , P4, ,O₂ , Na, Al, O3, S8, and Mg, all have an oxidation number zero.
  • The oxidation state of ions that comprise of only one atom is the actual charge on the ion.
  • The oxidation state of hydrogen is +1, excluding when it is bonded to metals having two elements. For example, CaH2, its oxidation state is –1.
  • Fluorine and other halogens have an oxidation state equal to –1 when they appear as a form of halide ions in their compounds.

Since the inert pair effect increases as we go down the group and become more predominant, therefore, the stability of +2 oxidation state goes on increasing down the group. Therefore, gallium, indium are mostly found in +1 oxidation state.

Thus, we concluded that Boron shows analogous behaviour with silicon. Every compound of Boron have +3 oxidation state, while as we go down the the oxidation state become +1 and +3. For example, gallium, indium, etc.

learn more about oxidation state:

brainly.com/question/25551544

#SPJ4

4 0
2 years ago
Convert 125 g to kilograms
joja [24]
Move the decimal place to the left 3 digits.
0.125
3 0
4 years ago
Read 2 more answers
if the following is one strand of DNA what would be the corresponding strand of mRNA that is sequenced from it
Dmitrij [34]

Answer:

U A G C C A U C G G A U C C G A U

Explanation:

In DNA, A=T, C=G, and vice versa. RNA has U instead of T. So dna to rna: adenine = uracil, thymine = adenine, cytosine = guanine, and guanine = cytosine.

7 0
3 years ago
How many isomers are there with the formula c3h4? include both structural and geometric isomers?
sleet_krkn [62]
There are three possible Isomers for Molecular Formula C₃H₄. Isomers are;

                                           1) Propyne

                                           2) Propa-1,2-diene

                                           3) Cyclopropene

Structures of all three isomers are given below.

There are no geometrical isomers for given molecular formula because geometrical isomers are formed in compounds containing double bond with at least two bulky groups at both sp² hybridized carbons. In given isomers, propyne does not contain any double bond, Propa-1,2-diene is symmetrical in nature while cyclopropene is a 3-membered ring. And for cycloalkenes there must be other groups attached to ring other than Hydrogen atom, hence cyclopropene does not contain any other group, so it can not show geometrical isomerism.

7 0
3 years ago
In calculating the concentration of [Cu(NH3)4]2+[Cu(NH3)4]2+ from [Cu(H2O)4]2+[Cu(H2O)4]2+, the stepwise formation constants are
tamaranim1 [39]

Answer:

11.1×10^12

Explanation:

β4= K1× K2 × K3 × K4

β4= 1.90×10^4 × 3.90×10^3 × 1.00×10^3 ×1.50×102

β4=11.1×10^12

The overall formation (stability) constant β4= K1× K2 × K3 × K4. Hence the answer.

3 0
4 years ago
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