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Slav-nsk [51]
3 years ago
9

Write a balanced equation showing how this nucleus decays to form an α particle: thorium−230.

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
6 0
When   an  atomic  nucleus  emits  an  alpha  particle  it  decay  into  an atom   with atomic  number  2  less   and   mass number  4  less.  Thus  Thorium   230   decay    as  follows.

230 90Th  -------> 226  88Th  +  4 2 He

thorium  is  in  the  atomic  number   90  thus  it  during   alpha decay  it reduces  to  atomic  number  88  while  its  230   mass  number  reduces  to   226
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How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
EastWind [94]

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

8 0
3 years ago
A certain indicator has a color chart that shows that when the indicator is yellow, the solution is acidic. What is true about a
bija089 [108]
It’s acidic?
It tastes sour
It has at least one hydrogen molecule
4 0
4 years ago
Write the formula for potassium nitride? <br> (show work)<br> CAN SOMEONE PLEASE HELP?
ohaa [14]

Answer:

It should b KNO3

Explanation:

one Potassium (K) and three Nitrite (NO3)

8 0
3 years ago
Who is generally credited with developing the process of using heat?
galina1969 [7]

Answer:

Robert Boyle

Explanation:

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6 0
2 years ago
I performed an experiment and mixed copper nitrate and potassium iodide. When they reacted, they formed a precipitate, even thou
Alexus [3.1K]

Answer:

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

Explanation:

The reaction performed in the experiment is;

2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2

The iodide ions reduces Cu^2+ to Cu^+ which is insoluble in water hence the precipitate. This is so because iodine is a good oxidizing agent seeing that it requires one electron to fill its outermost shell. Potassium on the other hand is a good reducing agent since it easily looses its one electron.

The oxidation - reduction equation is as follows;

2Cu2^+ + 2e ----> 2Cu^+ reduction half equation

2I^- ----> I2 + 2e. Oxidation half equation

Balanced redox reaction equation;

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

3 0
3 years ago
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