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3 years ago

Write a balanced equation showing how this nucleus decays to form an α particle: thorium−230.

1 answer:

6 0

When an atomic nucleus emits an alpha particle it decay into an atom with atomic number 2 less and mass number 4 less. Thus Thorium 230 decay as follows.

230 90Th -------> 226 88Th + 4 2 He

thorium is in the atomic number 90 thus it during alpha decay it reduces to atomic number 88 while its 230 mass number reduces to 226

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Calculate the mass/volume percent of a NaCl solution in which 140 g of NaCl is dissolved in enough water to give a total volume

Len [333]

Mass per volume percent is simply calculated by getting the ratio of the mass in g of solute and the volume in mL of the solution multiplied by 100 percent. In the problem, we are given all the required values. Calculation is as follows:

%w/v = 140 / 1590 x 100 = 8.81%

7 0

3 years ago

can someone please help me ill give brainest? Will the velocity of the book change as it moves across the surface WITH friction?

Lady bird [3.3K]

Answer:

Yes, it will.

Explanation:

The friction of the surface will tug at the book and lower it's velocity, causing it to slow down.

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3 years ago

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In a polyatomic ion, the -ate ending indicates one ____ oxygen than the -ite ending.

grigory [225]

In a polyatomic ion, the ate ending indicates one more oxygen than the ite ending. D. more.

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3 years ago

Under which conditions would the solubility of a gas be greatest? high pressure and high temperature high pressure and low tempe

kiruha [24]

Option B: high pressure and low temperature

A gas is more soluble under high pressure and low temperature conditions.

On increasing temperature of a gas, its kinetic energy increases. The increase in kinetic energy increases the motion of particles of gas this causes most of the gaseous particles to escape from the gas phase. Thus, less particles are available to dissolve in liquid and solubility decreases.

The effect of pressure on solubility of gas can be explained with the help of Henry's law. According to the law, at constant temperature, solubility of gas and partial pressure of gas are related to each other as follows:

$p=k_{h}c$

Here, p is the partial pressure of the gas, $k_{h}$ is Henry's law constant, and

c is the concentrate of the gas.

According to above relation, concentration of gas decreases on decreasing partial pressure. Thus, on increasing pressure, concentration of gas increases this increases the solubility of gas in liquid.

Therefore, solubility of gas is greatest at high pressure and low temperature.

4 0

3 years ago

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8. The standard enthalpy of formation of RbF(s) is –557.7kJ/mol and the standard enthalpy of formation of RbF(aq, 1 m) is –583.8

garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7) kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

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3 years ago