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Slav-nsk [51]
3 years ago
9

Write a balanced equation showing how this nucleus decays to form an α particle: thorium−230.

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
6 0
When   an  atomic  nucleus  emits  an  alpha  particle  it  decay  into  an atom   with atomic  number  2  less   and   mass number  4  less.  Thus  Thorium   230   decay    as  follows.

230 90Th  -------> 226  88Th  +  4 2 He

thorium  is  in  the  atomic  number   90  thus  it  during   alpha decay  it reduces  to  atomic  number  88  while  its  230   mass  number  reduces  to   226
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Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

C_{O_2}=8.55\times 10^3g/L

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = \frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L

Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

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Answer:

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According to the Gay- Lussac's Law,

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As the temperature increase, the pressure also increase.

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Answer:

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