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Novosadov [1.4K]
2 years ago
7

SHOW ALL WORK AND INCLUDE UNITS

Chemistry
1 answer:
Sliva [168]2 years ago
6 0

Answer:

+375.2 KJ.

Explanation:

The balanced equation for the reaction is given below:

H₂ + F₂ —> 2HF ΔH = +536 KJ

From the balanced equation above,

2 moles of HF required +536 KJ .

Finally, we shall determine the heat required to produce 1.4 mol of hydrogen fluoride, HF. This is illustrated below:

From the balanced equation above,

2 moles of HF required +536 KJ .

Therefore, 1.4 moles of HF will require = (1.4 × 536)/2 = +375.2 KJ

Thus, +375.2 KJ of heat energy is required.

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Answer:

Explanation:

-The Atomic Radius of an element is the distance between the center of an atom

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- nucleus and the negative charge of all the atom's electrons.

5 0
3 years ago
Why is it important that acids and bases have different properties?
vaieri [72.5K]
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If I stretch a rubber band across the room you are transforming energy in to
mihalych1998 [28]
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3 years ago
The temperature will decrease the rate of reactions.
Dahasolnce [82]

Answer:

true?

Explanation:

3 0
3 years ago
Student weighs out 0.287 g of ascorbic acid (H2CH06), a diprotic acid, into a 250. mL k and dilutes to the mark with distilled w
pav-90 [236]

Explanation:

It is given that mass of ascorbic acid = 0.287 g

As molar mass of ascorbic acid is 176.12 g/mol. Hence, calculate its number of moles as follows.

moles ascorbic acid = \frac{\text{mass ascorbic acid}}{\text{molar mass ascorbic acid}}

           moles ascorbic acid = \frac{0.287 g}{176.12 g/mol}

                                             = 1.63 \times 10^{-3} mol

So, moles of H^{+} = 2 \times \text{(moles ascorbic acid)}

                                 = 2 \times (1.63 \times 10^{-3} mol)

                                 = 3.26 \times 10^{-3} mol

Therefore, moles NaOH required = moles H^{+}

     moles NaOH required = 3.26 \times 10^{-3} mol

Now, we will calculate the volume of NaOH as follows.

          volume NaOH = \frac{\text{moles NaOH required}}{\text{molarity NaOH}}

            volume NaOH = \frac{3.26 \times 10^{-3} mol}{0.0500 M)}

                                    = 0.0652 L

or,                                = 65.2 mL              (as 1 L = 1000 ml)

Thus, we can conclude that the volume of NaOH required is 65.2 ml.

7 0
3 years ago
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