good morning to you all! someone please answer this, ill give you brainliest and you will earn 50 points.

Physics

2 answers:

Shalnov [3]2 years ago

3 0

Natural hazards do not have to be natural disasters. What are some of the ways modern technology can help prevent future natural disasters?

Satellite imaging to make future disaster prediction
Monitoring seismic activity using seismographs

Satellite imaging helps in predicting disasters like hurricane. Before hurricane, the satellite can help detect the movements in ocean.

Seismographs are the devices that respond to the ground shaking before volcanic eruption, earthquake and explosions.

vovikov84 [41]2 years ago

3 0

The correct ones are

Satellite imaging to make future disaster prediction
Monitoring seismic activity using seismograph.

The reasons are

Satellite imaging can find out the current weather status by which we can be warned about Tsunami,cyclones etc.
Seismic waves monitoring can help us to find out at where the next earth quake going to happen

You might be interested in

If 128 v is required to push 4.00 A of current though a resistor, what is the resistance

prisoha [69]

Answer:

32.0 Ω

Explanation:

Ohm's law:

V = IR

128 V = (4.00 A) R

R = 32.0 Ω

8 0

3 years ago

a pulley is used to lift a 2000 N safe over frosty's head. the safe is lifted 6m in 4s by Rudolph. how much power did Rudolph us

garri49 [273]

Answer:

3000W

Explanation:

Given parameter:

Weight of safe = 2000N

Height of lift = 6m

Time = 4s

Unknown:

Power used by Rudolph = ?

Solution:

Power is the rate at which work is being done. It is expressed as:

Power = $\frac{Work done }{Time taken}$

Work done = Weight x height = 2000 x 6 = 12000J

Power = $\frac{12000}{4}$ = 3000W

8 0

3 years ago

A car is moving southwest at a velocity of 10 meters per second. Five seconds later, it's going 40 meters per second. What was t

Inga [223]

If "during this time" refers to the 5 second interval mentioned above, then the average acceleration is

$\bar a=\dfrac{v-v_0}{t-t_0}=\dfrac{40\,\frac{\mathrm m}{\mathrm s}-10\,\frac{\mathrm m}{\mathrm s}}{5\,\mathrm s-0\,\mathrm s}$

Notice that we took the start time to be the start of the 5 second interval and set that to $t_0=0$ . The starting velocity $v_0$ is the velocity measured at the start of the interval, and $v$ is the velocity measured at its end.