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arsen [322]
2 years ago
12

good morning to you all! someone please answer this, ill give you brainliest and you will earn 50 points.

Physics
2 answers:
Shalnov [3]2 years ago
3 0

Natural hazards do not have to be natural disasters. What are some of the ways modern technology can help prevent future natural disasters?

  • <em>Satellite</em><em> </em><em>imaging</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>future</em><em> </em><em>disaster</em><em> </em><em>prediction</em>
  • <em>Monitoring</em><em> </em><em>seismic</em><em> </em><em>activity</em><em> </em><em>using</em><em> </em><em>seismographs</em>

<u>Satellite</u><u> </u><u>imaging</u><u> </u><u>helps</u><u> </u><u>in</u><u> </u><u>predicting</u><u> </u><u>disasters</u><u> </u><u>like</u><u> </u><u>hurricane</u><u>.</u><u> </u><u>Before</u><u> </u><u>hurricane</u><u>,</u><u> </u><u>the</u><u> </u><u>satellite</u><u> </u><u>can</u><u> </u><u>help</u><u> </u><u>detect</u><u> </u><u>the</u><u> </u><u>movements</u><u> </u><u>in</u><u> </u><u>ocean</u><u>.</u><u> </u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u>Seismographs</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>devices</u><u> </u><u>that</u><u> </u><u>respond</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>ground</u><u> </u><u>shaking</u><u> </u><u>before</u><u> </u><u>volcanic</u><u> </u><u>eruption</u><u>,</u><u> </u><u>earthquake</u><u> </u><u>and</u><u> </u><u>explosions</u><u>.</u>

vovikov84 [41]2 years ago
3 0

The correct ones are

  • Satellite imaging to make future disaster prediction
  • Monitoring seismic activity using seismograph.

The reasons are

  • Satellite imaging can find out the current weather status by which we can be warned about Tsunami,cyclones etc.
  • Seismic waves monitoring can help us to find out at where the next earth quake going to happen
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Answer:

V1 = 2221.33 L

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The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:

P_1V_1=nRT_1   (1)

And also for the situation in which the variables T, V and P has changed:

P_2V_2=nRT_2   (1)

R: constant of ideal gases = 0.082 L.atm/mol.K

For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}

Next, you equal these equations an solve for T2:

\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}

Finally you replace the values of P2, V2, T1 and T2:

V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L

Hence, the initial volume of the gas is 2221.33 L

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