[04.05] An atom has an atomic number of 12 and a mass number of 25. How many neutrons does the atom have?

Acceleration is defined as the rate of change for which of the following? Question 4 options: time position velocity displacemen

vovangra [49]

Acceleration can be defined as the rate of change in the velocity of an object. Option C is correct.

<h3>What is Acceleration?</h3>

It is defined as the rate of change in velocity.

It can also be defined as the rate of change in position in a particular direction.

$a = \dfrac {v-u}t\ \ \ \ \rmor}\\\\a = \dfrac {\Delta v }t$

Where,

$a$ - acceleration

$\Delta v$ - change in velocity

$t$ - time

Therefore, acceleration can be defined as the rate of change in the velocity of an object.

Learn more about Velocity:

brainly.com/question/2239252

4 0

2 years ago

What is someones target heart rate at 70% at age 17

baherus [9]

Answer: normal

Explanation:

6 0

2 years ago

Why is it important for car designers to keep accurate records of their experimental procedures

storchak [24]

Like all experiments, it's important to keep records of the their experiment procedures so future car designers and experimenters can compare and contrast their results from their experiment and improve their experiment accordingly. I'm pretty sure this is it. Stay cool my man.

5 0

3 years ago

In order for an object to move, the forces acting on it must be

spin [16.1K]

In order for an object to move, the forces acting on it must be ''unbalanced forces'' because balanced forces means equal canceling each other out so 0 to 0 while unbalanced means one side or thing is higher or lower than another and that makes objects move which are unbalanced since a side is not equal to the other.

8 0

2 years ago

Bill is farsighted and has a near point located 125 cm from his eyes. Anne is also farsighted, but her near point is 75.0 cm fro

Arisa [49]

Answer:

a) The closest object Anne can see, while wearing Bill's glasses is at approximately 22.39 cm relative to her eyes

b) The closest object Bill can see while wearing Anne's glasses is at approximately 26.38 cm relative to his eyes

Explanation:

The point where Bill has a near point = 125 cm

The point where Anne has a near point = 75.0 cm

Their vision are both corrected to the normal near point = 25.0 cm

The distance of their glasses from the eye, d = 2.0 cm

The lens formula is presented as follows;

$\dfrac{1}{f} =\dfrac{1}{d_0} +\dfrac{1}{d_i}$

The required distance of the of the object from Bill's glass, $d_{oB}$ = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Bill's glass, $d_{iB}$ = -(125 cm - 2.0 cm) = -123 cm

Therefore, for Bill, we have;

$\dfrac{1}{f_B} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}$

Plugging in the values gives;

$\dfrac{1}{f_B} =\dfrac{1}{23} -\dfrac{1}{123} = \dfrac{100}{2,829}$

Therefore;

$f_B$ = 2,829/100 cm = 28.29 cm

The required distance of the of the object from Anne's glass, $d_{oA}$ = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Anne's glass, $d_{iA}$ = -(75 cm - 2 cm) = -73 cm

The focal length for Anne is therefore;

$\dfrac{1}{f_A} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}$

Plugging in the values gives;

$\dfrac{1}{f_A} =\dfrac{1}{23} -\dfrac{1}{73} = \dfrac{50}{1,679}$

Therefore, we have;

$f_A$ = 1,679/50 cm = 33.58 cm

a) When Anne wears Bill's lasses, we have;

$\dfrac{1}{f_B} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}$

Therefore, we get;

$\dfrac{1}{28.29} =\dfrac{1}{d_{0A}} -\dfrac{1}{73}$

$\dfrac{1}{d_{0A}} = \dfrac{1}{28.29} + \dfrac{1}{73} = \dfrac{10,129}{206,517}$

$d_{0A}$ ≈ 20.39 cm

The distance of the closest object Anne can see, from her eye, $d_{oe}$ = $d_{0A}$ + d

∴ $d_{oe}$ ≈ 20.39 cm + 2.0 cm = 22.39 cm

The distance of the closest object Anne can see, from her eye, $d_{oe}$ ≈ 22.39 cm

b) The closest object that can be seen when Bill wears Anne's glasses, we have;

$\dfrac{1}{f_A} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}$

Therefore;

$\dfrac{1}{33.58} =\dfrac{1}{d_{0B}} -\dfrac{1}{123}$

$\dfrac{1}{d_{0B}} = \dfrac{1}{33.58} +\dfrac{1}{123} = \dfrac{7,829}{206,517}$

∴ $d_{oB}$ ≈ 26.38 cm

The closest object Bill can see while wearing Anne's glasses, $d_{oB}$ ≈ 26.38 cm.

6 0

2 years ago

[04.05] An atom has an atomic number of 12 and a mass number of 25. How many neutrons does the atom have?​

[04.05] An atom has an atomic number of 12 and a mass number of 25. How many neutrons does the atom have?