Answer:constant of variation(k) is, 250.
Step-by-step explanation:
The inverse variation says that:
then, the equation is in the form of :
....[1] where, k is the constant of variation
As per the statement:
Suppose that y varies inversely with x.
then,
by definition of inverse variation we have;
When x = 2.5 and y = 100 then
Substitute these in [1] we have;
Multiply 2.5 both sides we have;
or
k = 250
⇒
Therefore, the constant of variation is, 250 and the equation we get
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Step-by-step explanation:
We are giiven with two realms: 36 students who passed test 1 and <span>38 who passed test 2 in which 42 students overall took the test. to determine U' or those who didn't pass either of the tests, then we use the formula:
A or B = (A+B)-AandB
A/B = (36+38)-AandB= 74-AandB
42 = A+ B - AandB + U'; 42 = 74- AandB+ U'
where U' is the number who did not pass
U'= -32 + AandB
U' cannot be negative but can be zero,
AandB = 32 @ minimum number of those who fail.
AandB cannot be greater than 38 but can be greater than 36, hence
U' = -32 + 38 @ maximum number of those who fail.
Answer then is 6.
</span>
Answer:
x=-3
Step-by-step explanation:
follow the PEMDAS method then see if the 2 equation equal each other after plugging in the x.
Step-by-step explanation:
Hey there!
<u>Firstly </u><u>find </u><u>slope </u><u>of</u><u> the</u><u> </u><u>given</u><u> equation</u><u>.</u>
Given eqaution is: 3x + 2y = 5.......(i)
Now;


Therefore, slope (m1) = -3/2.
As per the condition of parallel lines,
Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.
The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;
(y-y1) = m2 (x-x1)
~ Keep all values.

~ Simplify it.



Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.
<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
2.0/4.0
Step-by-step explanation: