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2 years ago

How many odd 2-digit positive integers greater than 30 are there?

Mathematics

2 answers:

alexgriva [62]2 years ago

6 0

Answer:

There are 70 two digit numbers that are greater than or equal to 30

Step-by-step explanation:

hope it helps you

ki77a [65]2 years ago

5 0

Answer:

Step-by-step explanation:

There are 100 -30 = 70 2-digit positive integers. Half of them are odd.

There are 35 odd 2-digit positive integers greater than 30.

<em>Additional comment</em>

For n = 1 .. 35, those numbers are 2n+29.

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Question 4 Multiple Choice Worth 1 points)<br> (01.02 MC)<br> Solve for :<br> 2 x -<br> (x - 2) = 4x

oee [108]

Answer:

$\small \sf \frac{2}{3} = x \\$

Step-by-step explanation:

Solve for x;

2x - ( x - 2 ) = 4x

distribute minus sign through parantheses

2x - x + 2 = 4x

combine like terms

x + 2 = 4x

subtract x from both side

x - x + 2 = 4x - x
2 = 3 x

Divide each side by 3

$\small \sf \frac{2}{3} = \frac{3x}{3} \\$

$\small \sf \frac{2}{3} = x\: \\$

3 0

3 years ago

a model rocket is launched from the ground with an initial velocity of 60 feet per second. the function g(t)= -16t^2 + 60t repre

Lemur [1.5K]

If we use our trusty ti's this will be a breeze
domain is the numbers we can use
obviously we can't have negative time so therefor the domain is all positive integers (0,1,2,2.3, 3/2,3,pi...)

zeroes is when you set absolute max using ti is
remember vertex form which is
max height of something in
ax^2+bx+c form is -b/2a
-16t^2+60t+0
a=-16
b=60
-60/(2 times -16)
-60/-32=30/16=15/8=1 and 7/8 so subsitute for t
g(15/8)=-16(15/8)^2+60(15/8)=225/4=56.25=max height

zeroes is when the equation equals 0
so set it to zero
0=-16t^2+60t
factor
0=(-4t)(4x-15)
set each to zero
-4x=0
x=0
4x-15=0
add 15
4x=15
divid 4
x=15/4
so the zeros are t=0 and t=15/4

domain is all the nuumbers that can be used logically for time
logically, we cannot have negative time, so all real positive
[0,∞)
(that means from 0 to infinity includng 0 so 0<span><</span>t<∞))

range is the output
output=height
we find the min height and max height
min=0
max=56.25
so range=0 to 56.25 or
[0,56.25]

max height=56.25 ft (15/8 seconds)
zeroes=0 sec and 15/4 sec
domain=all real positive numbers including zero or [0, ∞)
range=[0,56.25]

3 0

2 years ago

My circumference is 20 cm what is my diameter and radius?

Musya8 [376]

Answer:

The diameter of the circle would be: 6.4 cm. rounded or 6.36619772 cm.

The radius of the circle would be: 3.2 cm. rounded or 3.18309886 cm.

Step-by-step explanation:

<h3>The diameter can be solved using: D = $\frac{C}{\pi }$ </h3>

So, the first step would be : D = $\frac{20}{\pi }$

Then : D = 20 ÷ $\pi$

Finally, the answer will be : 6.36619772 cm. or 6.4 cm.

<h3>The Radius can be Solved using: r = $\frac{c}{2\pi }$ </h3>

The first step would be : r = $\frac{20}{2\pi }$

Then : 20 ÷ 6.2831853071796 (2 $\pi$ )

Finally, the answer will be : 3.18309886 cm. or 3.2 cm.

7 0

2 years ago

Solve the equation for y.<br><br> 6y+x=8

iVinArrow [24]

Answer:

The correct answer is $\bold{y = -\frac{1}{6}x+\frac{4}{3}}$ .

Step-by-step explanation:

We want to solve for y in the given equation. We can do this by rearranging the equation and using operational techniques to simplify.

$6y + x = 8 \ $\tex Subtract x from both sides of the equation.$

$6y + x - x = 8 - x \ $\tex Carry out the operation.$

$6y = 8 - x \ $\tex Rearrange so the equation lists the variables first and the constants second.$

$6y = -x + 8 \ $\tex Create a coefficient for the x-variable (this is -1).$

$6y = -1x + 8 \ $\tex Divide by 6 on both sides of the equation in order to isolate the y-variable.$

$\frac{6y}{6}=\frac{-1x}{6} + \frac{8}{6} \ $\tex Carry out this operation by simplifying the fractions and dividing out the operations accordingly.$

$y = -\frac{1}{6}x+\frac{4}{3} \ $\tex Be sure to verify that all fractions and terms are simplified as far as they can be and that the equation is written in proper syntax.$