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Blizzard [7]
2 years ago
6

(0.2)^3 A. 0.04 B. 3.2 C. 0.008 D. 0.6

Mathematics
2 answers:
RoseWind [281]2 years ago
8 0
<h3>Solution:</h3>

1. <u>Change 0.2 into fraction form.</u>

0.2 = \frac{2}{10}

2. <u>Simplify (2/10)³.</u>

(\frac{2}{10})^{3}

⇒ (\frac{2}{10})(\frac{2}{10})(\frac{2}{10})

⇒ \frac{8}{1000}

3. <u>Change 8/1000 into decimal form.</u>

<u />\frac{8}{1000} = \frac{0.8}{100} = \frac{0.08}{10}  = \frac{0.008}{1}  = 0.008

Thus, Option C is correct.

erma4kov [3.2K]2 years ago
6 0

Step-by-step explanation:

The exponent of a number describes how many times to multiply the number by itself.

(0.2)^3=0.2 \times 0.2\times 0.2

<u>Multiply;</u>

0.2 \times 0.2 \times 0.2

0.04 \times 0.2

0.008

\boxed{C. \: 0.008 \: is \: the \: correct \: option.}

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Need help asap please
Lelechka [254]

Answer:

The answer is row C

Step-by-step explanation:

6 - 3 = 3

3 0
2 years ago
Hi need help early giving out 98 points<br> Thank you : )
Setler [38]

Answer:

1)f(x)=2(3)^x

2)f(x)=10(2)^x

3)Graph attached

4) Amber will have 192 and 3145728 shares on day 3rd and 10th respectively

Ben will have 54 and 118,098 shares on day 3rd and 10th respectively

Carter will have 80 and 10240 shares on day 3rd and 10th respectively

5)the graph has moved 45 unit up

6)Amber's posts will travel fastest

7)Amber' function

Step-by-step explanation:

1)

Ben shares posts with two friends and then they share with 3 more everyday, so her the growth rate is 3

f(x)=2(3)^x

x=number of days

2)

Carter shares posts with ten friends and then they share with 2 more everyday, so her the growth rate is 2

f(x)=10(2)^x

x=number of days

3)

Graph attached contain graph's of following

Ben's f(x)=2(3)^x in red

Carter's f(x)=10(2)^x in blue

Amber's f(x)=3(4)^x in green

4)

Finding how many shares each student will get on day 3 and day 10:

For Amber:

substituting x=3,

f(x)=3(4)^3

     = 192

Now substituting x=10,

f(x)= 3(4)^10

     = 3145728

Amber will have 192 and 3145728 shares on day 3rd and 10th respectively

For Ben:

substituting x=3,

f(x)=2(3)^3

     = 54

Now substituting x=10,

f(x)= 2(3)^10

     = 118,098

Ben will have 54 and 118,098 shares on day 3rd and 10th respectively

For Carter:

substituting x=3,

f(x)=10(2)^3

     = 80

Now substituting x=10,

f(x)= 10(2)^10

     = 10240

Carter will have 80 and 10240 shares on day 3rd and 10th respectively

5)

If Amber's graph changes to

f'(x)=3(4)^x +45

then as per translation, it means the graph has moved 45 unit up from original position as shown in attached graph

original f(x)=3(4)^x in green

translated f'(x)=3(4)^x +45 in blue

6)

In exponential function the base of function effects the growth and in given cases of Amber, Ben and Carter; base of Amber's function is greatest i.e 4 other two have 2 and 3.

So Amber's posts will travel fastest

7) A post with fewer friends initially and then more shares like Amber. Because at the end of the day the growth rate is important and as explain above the number of shares i.e base of exponential function is important.

Hence for more shares and likes Amber' function is the best choice !

3 0
3 years ago
What is 190×76=? <br> Please help!
mart [117]
190*76 is equal to 14440.
6 0
3 years ago
Read 2 more answers
You have two lines. Line A measures 12/16, and line B measures 3/4.
hram777 [196]

Answer:

B

Step-by-step explanation:

Let's compare the two values of 12/16 and 3/4.

Notice that 12/16 isn't a simplified fraction; both the numerator and denominator are divisible by 4. So divide the top and bottom by 4:

12 / 4 = 3

16 / 4 = 4

We are left with:

12/16 = 3/4

Now, we see that Line A and Line B are equal in length, so the answer is B.

<em>~ an aesthetics lover</em>

8 0
3 years ago
Read 2 more answers
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PolarNik [594]
First turn 1/2 to 2/4 so you have a common denominator.
Next turn the mixed numbers into improper fractions:
11 3/4 --> 47/4 and 8 2/4 --> 34/4
Subtract:
47/4 - 34/4 = 13/4
Divide:
13/4 = 3.25
3.25/2 --> 1.625 or 1 5/8
Therefore, he will have to place it 1 5/8 feet from each side

Hope this helps!
6 0
3 years ago
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