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2 years ago

What happens to the period of the motion when the spring constant increases? Does it increase, decrease, or stay the same?

Physics

1 answer:

IRINA_888 [86]2 years ago

4 0

Answer:

The answer would be Increase becaause the springs constantmotion is increasing.

Explanation:

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I need the answer ASAP. Please explain your answer too. 20 points!

Oksana_A [137]

Answer; g

Explanation: the human is a lot smaller than the train

7 0

2 years ago

A convex lens can produce a real image but not a viral image<br> a. true<br> b. false

serious [3.7K]

The answer is true a convex lens can produce a real image but not a viral image

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3 years ago

The core of a certain reflected reactor consist of a cylinder 10 ft high 10 ft in diameter The measured maximum-to-average flux

Westkost [7]

Answer:

The maximum power density in the reactor is 37.562 KW/L.

Explanation:

Given that,

Height = 10 ft = 3.048 m

Diameter = 10 ft = 3.048 m

Flux = 1.5

Power = 835 MW

We need to calculate the volume of cylinder

Using formula of volume

$V =\pi r^2 h$

Put the value into the formula

$V=\pi\times(1.524)^2\times 3.048$

$V= 22.23\m^3$

$V = 22.23\times10^{3}\ Liter$

We need to calculate the maximum power density in the reactor

Using formula of power density

$P=\dfrac{E}{V}$

Where, P = power density

E = energy

V = volume

Put the value into the formula

$P=\dfrac{835\times10^{6}}{22.23\times10^{3}}$

$P=37561.85 = 37.562\times KW/L$

Hence, The maximum power density in the reactor is 37.562 KW/L.

6 0

3 years ago

PLEASE HURRYYYy THIS IS DUE IN 5 minutes!!!!!!

Vilka [71]

Answer:

there is no momentum

Explanation:

6 0

3 years ago

A uniform solid sphere has mass m= 7 kg and radius r= 0. 4 m. What is its moment of inertia about an axis tangent to its surface

lilavasa [31]

The moment of inertia of a uniform solid sphere is equal to 0.448 $kgm^2$ .

<u>Given the following data:</u>

Mass of sphere = 7 kg.

Radius of sphere = 0.4 meter.

<h3>How to calculate moment of inertia.</h3>

Mathematically, the moment of inertia of a solid sphere is given by this formula:

$I=\frac{2}{5} mr^2$

<u>Where:</u>

I is the moment of inertia.

m is the mass.

r is the radius.

Substituting the given parameters into the formula, we have;

$I=\frac{2}{5} \times 7 \times 0.4^2\\\\I=2.8 \times 0.16$

I = 0.448 $kgm^2$ .

Read more on inertia here: brainly.com/question/3406242

4 0

2 years ago