All categories

3 years ago

If you travel 450 meters in 40 seconds, what is your average speed in meters per

Physics

2 answers:

Vedmedyk [2.9K]3 years ago

8 0

Answer:

The answer is a 11.25m/s

cupoosta [38]3 years ago

7 0

The answer should be A. 11.25

You might be interested in

A 10 gram ball is rolling at 3 m/s. What is the energy the ball has?

s344n2d4d5 [400]

Answer:

K = 0.045 J

Explanation:

It is given that,

Mass of a ball, m = 10 g = 0.01 kg

Speed of the ball, v = 3 m/s

To find,

The energy of the ball.

Solution,

Due to the motion of the ball, it will have kinetic energy. It can be given by the formula as follows :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.01\times 3^2\\\\K=0.045\ J$

So, the ball will have a kinetic energy of 0.045 J.

6 0

3 years ago

Car moves 5km East,3km south,2km West, 1km north find displacement<br>(please show me the way)

ddd [48]

Answer:

3.605551275463989

Explanation:

solve using Pythagorean theorem

4 0

2 years ago

Read 2 more answers

One student bangs two bricks together

Romashka-Z-Leto [24]

Answer:

This could be done if a stop watch is used to calculate the time taken to hear the echo and a rule should be used to calculate the distance between the bricks and the wall. Then divide distance by time

Explanation:

I hope this is what you need

PLEASE MAKE ME BRAINLIEST

7 0

3 years ago

The lowest possible temperature in outer space is 3.13 K. What is the rms speed of hydrogen molecules at this temperature? (The

Umnica [9.8K]

Answer:

$v_{rms} =196.59 m/s$

Given:

Temperature, T = 3.13 K

molar mass of molecular hydrogen, m = 2.02 g/mol = $2.02\times 10^{-3}kg/mol$

Solution:

To calculate the root mean squarer or rms speed of hydrogen molecule, we use the given formula:

$v_{rms} = \sqrt{\frac{3TR}{m}}$

where

R = rydberg's constant = 8.314 J/mol-K

Putting the values in the above formula:

$v_{rms} = \sqrt{\frac{3\times 3.13\times 8.314}{2.02\times 10^{-3}}}$

$v_{rms} =196.59 m/s$

5 0

3 years ago

A penguin slides at a constant velocity of 3.57 m/s down an icy incline. The incline slopes above the horizontal at an angle of

igomit [66]

Answer:t=0.81 s

Explanation:

Given

Penguin slides down with constant velocity of 3.57 m/s

as the Penguin Slides with constant velocity therefore $F_{net}$ is zero on Penguin

$F_{net}=mg\sin \theta -f_r$

$f_r=$ friction Force

$f_r=\mu mg$

$\mu =$ coefficient of Kinetic friction

$mg\sin \theta =\mu mg$

$\tan \theta =\mu$

$\mu =\tan 9.85=0.45$

after reaching on floor final velocity of penguin will be zero after time t

thus

$v=u+at$

here $a=\mu g$

$a=0.45\times 9.8=4.41$ (deceleration)

$0=3.57-4.41\times t$

$t=\frac{3.57}{4.41}=0.809$

$t=0.81 s$

8 0

3 years ago