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fiasKO [112]
2 years ago
11

A particular tank of oxygen gas contains 785 L at 21°C.If the pressure remains constant,what volume will the gas occupy if the t

emperature is changed to 28°C? (Write procedure)
Chemistry
1 answer:
garri49 [273]2 years ago
5 0
Make sure to list known values on the side. Based on the wording of the question, we know that pressure is constant and moles is constant. You can rearrange the ideal gas equation and solve for the volume.

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When electrons are added to the outer most shell of a carbon atom what does it form
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When electrons are added to the outermost shell of a carbon atom, it forms an anion.
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4 Infer is the reaction below possible?
mars1129 [50]
No, because hydrogen isn’t brought out of the equation
8 0
3 years ago
How many atoms are present in 65.39 g of zinc?
klio [65]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

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3 0
3 years ago
What is the mass in grams of 7.23 miles of dinitrogen trioxide?
nevsk [136]

Answer:

549.563868

Explanation:

1 mole is equal to 1 moles N2O3, or 76.0116 grams. so 76.0116 x 7.23 = 549.563868

3 0
3 years ago
An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
ozzi

In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

Thus, molecular formula of compound will be C_{6}H_{11}I.

4 0
3 years ago
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