All categories

3 years ago

PLEASE HELP!! 25 POINTS!! WILL MARK BRAINLIEST!!

Mathematics

1 answer:

iris [78.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

Given the functions, f ( x ) = x2 + x - 5 and g ( x ) = 4 x2 - 2 x + 1, perform the indicated operation. When applicable, state

elixir [45]

Answer:

(f-g)(x) = - 3 x² + 3 x -6

Step-by-step explanation:

Explanation:-

Given function f(x) = x² + x - 5

g(x) = 4 x² - 2 x + 1

(f-g)(x) = f(x) - g(x)

= x² + x - 5 - (4 x² - 2 x + 1)

= x² - 4 x² + x + 2 x - 5 -1

= - 3 x² + 3 x -6

(f-g)(x) = - 3 x² + 3 x -6

7 0

4 years ago

(19-4) times (14+4)+4 to the power of 2

Volgvan

Answer:

75,076

Step-by-step explanation:

19-4 = 15

14+4 = 18

15 x 18 = 270, then add 4 which equals 274.

274 x 274 = 75,076

8 0

4 years ago

What is the roots of f(x)=-x^2-6x-14

Nutka1998 [239]

Answer:

$x=-3\pm i \sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Algebra II

Imaginary roots: √-1 = i

Step-by-step explanation:

Step 1: Define function

f(x) = -x² - 6x - 14

Step 2: Set up

Set equation equal to 0: -x² - 6x - 14 = 0
Factor out -1: -(x² + 6x + 14) = 0
Divide both sides by -1: x² + 6x + 14 = 0

Step 3: Define variables

a = 1

b = 6

c = 14

Step 4: Find roots

Substitute: $x=\frac{-6\pm\sqrt{6^2-4(1)(14)} }{2(1)}$
Exponents: $x=\frac{-6\pm\sqrt{36-4(1)(14)} }{2(1)}$
Multiply: $x=\frac{-6\pm\sqrt{36-56} }{2}$
Subtract: $x=\frac{-6\pm\sqrt{-20} }{2}$
Factor: $x=\frac{-6\pm\sqrt{-1} \sqrt{20} }{2}$
Simplify: $x=\frac{-6\pm2i \sqrt{5} }{2}$
Factor: $x=\frac{2(-3\pm i \sqrt{5} )}{2}$
Divide: $x=-3\pm i \sqrt{5}$

8 0

3 years ago

1×1+9×(1/100)+1 ×(1/1,000)

Fittoniya [83]

Using PEMDAS
P = 1x1+9x(0.01)+1x(0.001)
E = no change
M = 1+0.09+0.001
D = no change
A = 1.091
S = no change
final answer is 1.091

8 0

3 years ago

Read 2 more answers

Please help!!! No links

Svetlanka [38]

Answer:

D Not similar

Step-by-step explanation:

For similar triangles the sides are always in proportions.

Here two sides are in proportion but third side isn't. So triangles are not similar.

8 0

3 years ago