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3 years ago

5

The james family bought their house in 2000 for $175,000 they sold their house in 2017 for $250,000, find the percent change in

the value of their house

1 answer:

Sergeu [11.5K]3 years ago

5 0

Answer:

42.9%

Step-by-step explanation:

The person above gave the correct answer, I got it right

250,000 -175,000 = 75,000

75,000 divided by 175,000 = 0.42857142857

0.42857142857 x 100 = 42.9

42.9% is the percent change

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According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

VikaD [51]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(X = 8) = 0.0037$

b

$P(X < 5) = 0.805$

c

$P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is $p = 0.267$

Generally data collected from this study follows binomial distribution because the number of trials is finite , there are only two outcomes, (covering , and not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable X we have that

$X \ \ \~ \ \ { B ( p , n )}$

The probability distribution function for binomial distribution is

$P(X = x ) = ^nC_x * p^x * (1 -p) ^{n-x}$

Considering question a

Generally the the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing is mathematically represented as

$P(X = 8) = ^{12} C_8 * (0.267)^8 * (1- 0.267)^{12-8}$

Here C denotes combination

So

$P(X = 8) = 495 * 0.000025828 * 0.28867947$

$P(X = 8) = 0.0037$

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when sneezing is mathematically represented as

$P(X < 5 ) =[P(X = 0 ) + \cdots + P(X = 4)]$

=> $P(X < 5 ) =[ ^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0} + \cdots + ^{12} C_4 * (0.267)^4 * (1- 0.267)^{12-4} ]$

=> $P(X < 5 ) = 0.02406 + 0.10516 + 0.21067 + 0.25580 + 0.20964$

=> $P(X < 5) = 0.805$

Considering question c

Generally the probability that fewer than half(6) covered their mouth when sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

$P(X > 6) = 1 - p(X \le 6)$

=> $P(X > 6) = 1 - [P(X = 0) + \cdots + P(X =6)]$

=> $P(X > 6)=1 - [^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0}+ \cdots + ^{12} C_4 * (0.267)^6 * (1- 0.267)^{12-6} ]$

=> $P(X > 6)= 1 - [0.02406 + \cdots + 0.0519 ]$

=> $P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

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wlad13 [49]

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RideAnS [48]

Answer:

Steve

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The equation gives the speed at impact, V metres per second, of an object dropped from a height of h metres. SHOW WORK From what

devlian [24]

Answer:

h = 17.65 m

Step-by-step explanation:

The given equation gives the speed at impact :

$v=\sqrt{2gh}$

h is height form where the object is dropped

Put v = 18.6 m/s in the above equation.

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3 years ago

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lyudmila [28]

The answer to the first one is A-4.7

Im not sure how, but i got 14.9 which would round to 15....

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